python 所有列中截止时间和开始时间的代码时间差

Question

我想在 pandas 列中找到截止时间和结束时间列表的差异，并在 df

中追加新时间

from datetime import datetime, date

out = datetime.combine(date.today(), datetime.strptime('00:15', '%H:%M').time())
print(out)

# output : datetime.datetime(2020,2,8,0,15)

reception time                     

2022-02-07 18:01:58
2022-02-07 05:05:05
2022-02-07 08:07:34
2022-02-07 09:05:33

find difference of all time and append in new column in df

Answer 1

如果您的 reception time 是数据框的一列，请使用：

df['diff'] = out - pd.to_datetime(df['reception time'])
print(df)

# Output
        reception time            diff
0  2022-02-07 18:01:58 0 days 06:13:02
1  2022-02-07 05:05:05 0 days 19:09:55
2  2022-02-07 08:07:34 0 days 16:07:26
3  2022-02-07 09:05:33 0 days 15:09:27

设置：

data = {'reception time': ['2022-02-07 18:01:58', '2022-02-07 05:05:05',
                           '2022-02-07 08:07:34', '2022-02-07 09:05:33']}
df = pd.DataFrame(data)
print(df)

# Output
        reception time
0  2022-02-07 18:01:58
1  2022-02-07 05:05:05
2  2022-02-07 08:07:34
3  2022-02-07 09:05:33

python 所有列中截止时间和开始时间的代码时间差

python code time difference with cut-off time and start time in all columns

python

time