有什么方法可以使用 SQL Server 2019 构建一个看起来像这样的 JSON 吗？

Question

我有这个 SQL 查询：

SELECT
    c.customer_name as name,
    c.customer_ssn as social_number,
    c.telephone as telephone,
    c.email as email,
    u.user_name as name
FROM
    Customer c
LEFT OUTER JOIN
    User u ON c.id_customer = u.id_customer
WHERE 
    c.id_customer = 2
FOR JSON PATH

SELECT * FROM Customer WHERE ID_CUSTOMER = 2
SELECT * FROM User WHERE ID_Customer = 2

这个查询 returns 这个 JSON :

[
    { 
      "name": "blablabla",
      "social": "123123123",
      "telephone": "91123123",
      "email": "blabla@gmail.com",
      "name":"blabla"
    }
]

有什么方法可以得到像这样的 JSON:

{
  "name": "blabla",
  "social_number": "123123123",
  "emails": [
    {
      "email": "blabla@gmail.com"
    },
    {
      "email": "blablabla@gmail.com"
    }
  ],
  "telephones": [
    {
      "number": "(604)6622141"
    },
    {
      "number": "(652) 2123223"
    }
  ],

感谢您的帮助！

我对编码和 Whosebug 还是个新手...如有任何错误，我们深表歉意！

Answer 1

您可以使用相关子查询，每个子查询 FOR JSON

SELECT
    c.customer_name as name,
    c.customer_ssn as social_number,
    telephones = (
        SELECT telephone
        FROM telephone t
        WHERE t.id_customer = c.id_customer
        FOR JSON PATH
    ),
    emails = (
        SELECT email
        FROM email e
        WHERE e.id_customer = c.id_customer
        FOR JSON PATH
    ),
    u.user_name as name
FROM
    Customer c
LEFT OUTER JOIN
    User u ON c.id_customer = u.id_customer
WHERE 
    c.id_customer = 2
FOR JSON PATH;

您也可以 APPLY

SELECT
    c.customer_name as name,
    c.customer_ssn as social_number,
    t.telephones,
    e.emails,
    u.user_name as name
FROM
    Customer c
LEFT OUTER JOIN
    User u ON c.id_customer = u.id_customer
OUTER APPLY (
        SELECT telephone
        FROM telephone t
        WHERE t.id_customer = c.id_customer
        FOR JSON PATH
) t(telephones)
OUTER APPLY (
        SELECT email
        FROM email e
        WHERE e.id_customer = c.id_customer
        FOR JSON PATH
) e(emails)
WHERE 
    c.id_customer = 2
FOR JSON PATH;

有什么方法可以使用 SQL Server 2019 构建一个看起来像这样的 JSON 吗？

Is there any way to build a JSON that looks like this using SQL Server 2019?

json

sql-server

for-json