分组相等值 - 聚合函数问题

Question

我创建了一个 table，其中列出了多个事件发生的地点。同一场地的同一活动可能有不同的价格。最后一列计算一个场所的总收入。

SELECT     venuename,
           eventname,
           totalprice,
           SUM(totalprice) OVER (PARTITION BY venuename)
    FROM venue
    INNER JOIN event e ON venue.venueid = e.venueid
    INNER JOIN listing l ON e.eventid = l.eventid;

venue	event	totalprice	sum
Venue A	Event A	5	30
Venue A	Event A	10	30
Venue A	Event B	5	30
Venue A	Event A	5	30
Venue A	Event B	5	30
Venue B	Event C	3	15
Venue B	Event D	6	15
Venue B	Event D	6	15

现在我想将相等的事件分组并计算一个场馆中一个事件的总收入。

结果应如下所示：

venue	event	totalprice	sum
Venue A	Event A	20	30
Venue A	Event B	10	30
Venue B	Event C	3	15
Venue B	Event D	12	15

我解决这个问题的想法是这样的：

SELECT venuename,
       eventname,
       SUM(totalprice),
       SUM(totalprice) OVER (PARTITION BY venuename)
FROM venue
INNER JOIN event e ON venue.venueid = e.venueid
INNER JOIN listing l ON e.eventid = l.eventid
GROUP BY eventname;

但这似乎不可能，因为 vanuename 也必须是聚合函数的一部分。但是我真的想不出解决这个问题的办法。

希望你们中的任何人都可以帮助我。

问候

Answer 1

您可以组合聚合和 window 函数

SELECT venuename,
       eventname,
       SUM(totalprice) totalprice,
       SUM(SUM(totalprice)) OVER (PARTITION BY venuename) sum
FROM venue
INNER JOIN event e ON venue.venueid = e.venueid
INNER JOIN listing l ON e.eventid = l.eventid
GROUP BY venuename, eventname;

分组相等值 - 聚合函数问题

grouping equal values - aggregate function problem

mysql

sql

group-by

aggregate