我如何展开输入按钮以桥接所有 3 行？即应该扩展到“0”“。”和 'Del'

Question

我正在使用 tkinter 创建我的第一个 GUI，但我遇到了一个问题。我如何展开小键盘的 'enter' 按钮（当您单击一个空框时打开）以覆盖当前那里的空 space？

如何指定小键盘的打开位置？

此外，如果有人有 shorter/faster 方法来编写此代码，我会对如何完成它感兴趣，因为虽然速度对我的项目来说不是非常必要，但拥有它总是很好。

代码如下：

import tkinter
from tkinter import *
from tkinter import simpledialog

def enumerate_row_column(iterable, num_cols):
    for idx, item in enumerate(iterable):
        row = idx // num_cols
        col = idx % num_cols
        yield row,col,item

class NumpadEntry(Entry):
    def __init__(self,parent=None,**kw):
        Entry.__init__(self,parent,**kw)
        self.bind('<FocusIn>',self.numpadEntry)
        self.bind('<FocusOut>',self.numpadExit)
        self.edited = False
    def numpadEntry(self,event):
        if self.edited == False:
            print("You Clicked on me")
            self['bg']= '#ffffcc'
            self.edited = True
            new = numPad(self)
        else:
            self.edited = False
    def numpadExit(self,event):
        self['bg']= '#ffffff'

class numPad(simpledialog.Dialog):
    def __init__(self,master=None,textVariable=None):
        self.top = Toplevel(master=master)
        self.top.protocol("WM_DELETE_WINDOW",self.ok)
        self.createWidgets()
        self.master = master
       
    def createWidgets(self):
        btn_list = ['1',  '2',  '3', '4',  '5',  '6', '7',  '8',  '0', '0',  '.',  'Del', 'Enter']
        # create and position all buttons with a for-loop
        btn = []
        # Use custom generator to give us row/column positions
        for r,c,label in enumerate_row_column(btn_list,3):
            # partial takes care of function and argument
            cmd = lambda x = label: self.click(x)
            # create the button
            cur = Button(self.top, text=label, width=5, height=3, command=cmd)
            # position the button
            cur.grid(row=r, column=c)                                              
            btn.append(cur)
           
    def click(self,label):
        print(label)
        if label == 'Del':
            currentText = self.master.get()
            self.master.delete(0, END)
            self.master.insert(0, currentText[:-1])
        elif label == 'Enter':
            self.ok()
        else:
            currentText = self.master.get()
            self.master.delete(0, END)
            self.master.insert(0, currentText+label)
    def ok(self):
        self.top.destroy()
        self.top.master.focus()

class App(Frame):
    def __init__(self,parent=None,**kw):
        Frame.__init__(self,parent,**kw)
        self.textEntryVar1 = StringVar()
        self.e1 = NumpadEntry(self,textvariable=self.textEntryVar1)
        self.e1.grid()

        self.textEntryVar2 = StringVar()
        self.e2 = NumpadEntry(self,textvariable=self.textEntryVar2)
        self.e2.grid()
       
if __name__ == '__main__':
    root = Tk()
    root.geometry("550x300")
    root.title("Monitoring Site GUI")
    app = App(root)
    app.grid()
   
    root.mainloop()

Answer 1

如评论所述：您需要使用 columnspan 在许多列中使用 space，并且 sticky (west-east) 在此 space.

    cur.grid(row=4, column=0, columnspan=3, sticky='we')

def createWidgets(self):

    # create and position all buttons
    btn = []

    # --- without ENTER ---

    btn_list = [
        '1',  '2',  '3',
        '4',  '5',  '6',
        '7',  '8',  '0',
        '0',  '.',  'Del'
    ]
    # Use custom generator to give us row/column positions
    for r,c,label in enumerate_row_column(btn_list, 3):
        # partial takes care of function and argument
        cmd = lambda x = label: self.click(x)
        # create the button
        cur = Button(self.top, text=label, width=5, height=3, command=cmd)
        # position the button
        cur.grid(row=r, column=c)                                              
        btn.append(cur)
        cur.grid(row=r, column=c)
        
    # --- only ENTER ---
    
    cmd = lambda x="Enter": self.click(x)
    # create the button
    cur = Button(self.top, text="Enter", width=5, height=3, command=cmd)
    # position the button
    cur.grid(row=4, column=0, columnspan=3, sticky='we')
    btn.append(cur)

我如何展开输入按钮以桥接所有 3 行？即应该扩展到“0”“。”和 'Del'

how do i expand the enter button to bridge all 3 rows? i.e should be extended to sit under both '0' '.' and 'Del'

python

user-interface

tkinter

numpad