如何在颤振中从联系人列表中随机选择号码？

Question

import 'package:flutter_phone_direct_caller/flutter_phone_direct_caller.dart';
import 'package:contacts_service/contacts_service.dart';

void checkContactPermission() async {
  var status = await Permission.contacts.status;
  var contacts = ContactsService.getContacts();
  var list = [contacts];
  var randomItem = (list.shuffle());
  if (status.isGranted) {
    FlutterPhoneDirectCaller.callNumber('randomItem');
  }
  if (!status.isGranted) {
    PermissionStatus permissionStatus = await Permission.contacts.request();
    if (status.isDenied) {
      PermissionStatus permissionStatus = await Permission.contacts.request();
    }
  }
}

这是我的代码，用于呼叫从联系人列表中随机选择的号码，但它正在呼叫一个甚至不在联系人列表中的号码。我应该改变什么？提前致谢

Answer 1

可以使用Flutter中的dart:math包生成一个介于1和contactList大小之间的随机数，然后通过生成的随机索引调用随机联系人即可。

import 'dart:math';

getRandomContact(List<Contact> contactsList){
   var random = new Random();
   var randomContactIndex = random.nextInt(contactsList.length);
   return contactsList[randomContactIndex];
}

你可以这样称呼它：

Contact randomContact = getRandomContact(contactsList);

Answer 2

Future<void> checkContactPermission() async {
  var status = await Permission.contacts.status;
  if (status.isGranted) {
    var contacts = await ContactsService.getContacts();
    var list = contacts;
    list.shuffle();
    var randomItem = (list.first.phones?.first.value);
    await FlutterPhoneDirectCaller.callNumber('$randomItem');
  }
  if (!status.isGranted) {
    PermissionStatus permissionStatus = await Permission.contacts.request();
    if (status.isDenied) {
      PermissionStatus permissionStatus = await Permission.contacts.request();
      }
    }
  }

这是我发现的有效方法

如何在颤振中从联系人列表中随机选择号码？

How to call randomly selected number from contact list in flutter?

dart

dart-pub

flutter

flutter-packages