return for 循环中函数的新列表以传入更新列表
return a new list from function in a for loop to pass in the updated list
我有一个方法将一个列表作为参数,对它执行一些操作,returns 新列表。但是,在我的 for..loop 中,我会继续传递更新的列表,直到 for..loop 完成。
有办法吗?
fun main(args: Array<String>) {
val listOfSeatRows = (1..127).toList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
getListOfSeatRows(listOfSeatRows, seat)
}
}
此方法采用列表和 return 更新后的列表。但是,在上面的 for..loop 中,我想传入从这个方法 return 编辑的列表
private fun getListOfSeatRows(listOfSeat: List<Int>, seatPosition: Seat): List<Int> {
return when(seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.windowed(listOfSeat.count() / 2).first()
}
Seat.B, Seat.R -> {
listOfSeat.windowed(listOfSeat.count() / 2).last()
}
}
}
enum class Seat(seat: Char) {
F('F'),
B('B'),
L('L'),
R('R')
}
递归
也许这将有助于根据您的代码进行一些增强:
var ss = 1
val listOfPass = listOf<Char>('F', 'L','B','R')
fun main(args: Array<String>) {
val listOfSeatRows = (1..127).toList()
val answer = getListOfSeatRows(
listOfSeatRows,
listOfSeatRows.count() / 2,
Seat.valueOf(listOfPass[0].toString())
)
println(answer)
}
private fun getListOfSeatRows(listOfSeat: List<Int>, count: Int, seatPosition: Seat): List<Int> {
val tempList: List<Int> = when (seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.windowed(count).first()
}
Seat.B, Seat.R -> {
listOfSeat.windowed(count).last()
}
else -> listOfSeat
}
if(count == 0 || count == 1) return listOfSeat
if (listOfPass.size > ss) {
val seat = Seat.valueOf(listOfPass[ss++].toString())
return getListOfSeatRows(tempList, count / 2, seat)
}
return listOfSeat
}
要么改变变量:
fun main(args: Array<String>) {
var listOfSeatRows = (1..127).toList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
listOfSeatRows = getListOfSeatRows(listOfSeatRows, seat)
}
}
或者您改变列表:
fun main(args: Array<String>) {
var listOfSeatRows = (1..127).toMutableList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
reduceListOfSeatRows(listOfSeatRows, seat)
}
}
private fun reduceListOfSeatRows(listOfSeat: MutableList<Int>, seatPosition: Seat) {
val half = listOfSeat.size / 2
when(seatPosition) {
Seat.F, Seat.L -> {
while (listOfSeat.size > half) listOfSeat.removeLast()
}
Seat.B, Seat.R -> {
while (listOfSeat.size > half) listOfSeat.removeFirst()
}
}
}
如果您坚持改变 属性,您的函数可以使用 take
/takeLast
:
来简化(并避免浪费创建多个中间列表)
private fun getListOfSeatRows(listOfSeat: List<Int>, seatPosition: Seat): List<Int> {
return when(seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.take(listOfSeat.size / 2)
}
Seat.B, Seat.R -> {
listOfSeat.takeLast(listOfSeat.size / 2)
}
}
}
我有一个方法将一个列表作为参数,对它执行一些操作,returns 新列表。但是,在我的 for..loop 中,我会继续传递更新的列表,直到 for..loop 完成。
有办法吗?
fun main(args: Array<String>) {
val listOfSeatRows = (1..127).toList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
getListOfSeatRows(listOfSeatRows, seat)
}
}
此方法采用列表和 return 更新后的列表。但是,在上面的 for..loop 中,我想传入从这个方法 return 编辑的列表
private fun getListOfSeatRows(listOfSeat: List<Int>, seatPosition: Seat): List<Int> {
return when(seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.windowed(listOfSeat.count() / 2).first()
}
Seat.B, Seat.R -> {
listOfSeat.windowed(listOfSeat.count() / 2).last()
}
}
}
enum class Seat(seat: Char) {
F('F'),
B('B'),
L('L'),
R('R')
}
递归 也许这将有助于根据您的代码进行一些增强:
var ss = 1
val listOfPass = listOf<Char>('F', 'L','B','R')
fun main(args: Array<String>) {
val listOfSeatRows = (1..127).toList()
val answer = getListOfSeatRows(
listOfSeatRows,
listOfSeatRows.count() / 2,
Seat.valueOf(listOfPass[0].toString())
)
println(answer)
}
private fun getListOfSeatRows(listOfSeat: List<Int>, count: Int, seatPosition: Seat): List<Int> {
val tempList: List<Int> = when (seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.windowed(count).first()
}
Seat.B, Seat.R -> {
listOfSeat.windowed(count).last()
}
else -> listOfSeat
}
if(count == 0 || count == 1) return listOfSeat
if (listOfPass.size > ss) {
val seat = Seat.valueOf(listOfPass[ss++].toString())
return getListOfSeatRows(tempList, count / 2, seat)
}
return listOfSeat
}
要么改变变量:
fun main(args: Array<String>) {
var listOfSeatRows = (1..127).toList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
listOfSeatRows = getListOfSeatRows(listOfSeatRows, seat)
}
}
或者您改变列表:
fun main(args: Array<String>) {
var listOfSeatRows = (1..127).toMutableList()
// Just loop until all the listOfPass has completed.
listOfPass.forEach { seatPass ->
val seat = Seat.valueOf(seatPass.toString())
// I want to pass in the new updated list not the same list
reduceListOfSeatRows(listOfSeatRows, seat)
}
}
private fun reduceListOfSeatRows(listOfSeat: MutableList<Int>, seatPosition: Seat) {
val half = listOfSeat.size / 2
when(seatPosition) {
Seat.F, Seat.L -> {
while (listOfSeat.size > half) listOfSeat.removeLast()
}
Seat.B, Seat.R -> {
while (listOfSeat.size > half) listOfSeat.removeFirst()
}
}
}
如果您坚持改变 属性,您的函数可以使用 take
/takeLast
:
private fun getListOfSeatRows(listOfSeat: List<Int>, seatPosition: Seat): List<Int> {
return when(seatPosition) {
Seat.F, Seat.L -> {
listOfSeat.take(listOfSeat.size / 2)
}
Seat.B, Seat.R -> {
listOfSeat.takeLast(listOfSeat.size / 2)
}
}
}