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Question

我正在使用 Firebird 3.0。我有 2 个表，我想通过一个查询获得以下结果，但我无法做到这一点。

用户Table

ID	USER_NAME
10	User1
20	User2
30	User3
40	User4
50	User5

CALL_HISTORY Table

ID	USER_ID	START_TIME	CALL_DIRECTION	STATUS	EXTEN	DURATION
1	10	09.02.2022	I	3	1007	63
2	10	09.02.2022	I	3	1007	37
3	10	09.02.2022	I	4	1007	0
4	20	09.02.2022	O	3	1008	33
5	20	09.02.2022	O	3	1008	47
6	20	09.02.2022	O	3	1008	10
7	30	09.02.2022	O	3	1028	121
8	30	09.02.2022	O	3	1028	37
9	30	09.02.2022	O	3	1028	73
10	30	09.02.2022	I	3	1028	61
11	40	09.02.2022	I	4	1013	0

预期结果

USER_NAME	NUM_INCOMING_CALL	DURATION_INCOMING_CALL	NUM_OUTGOING_CALL	DURATION_OUTGOING_CALL
User1	2	100	null	null
User2	null	null	3	90
User3	1	61	3	231

尝试

这是我试过的查询（还有一个dbfiddle）：

SELECT 
  outgoing_call.user_name,
  cast(incoming_call.num_incoming_call as bigint) as num_incoming_call,
  incoming_call.duration_incoming_call,
  cast(outgoing_call.num_outgoing_call as bigint) as num_outgoing_call,
  outgoing_call.duration_outgoing_call
from
  (select user_id, (select user_name from "USERS" where id=sch.user_id) user_name, count(id) num_outgoing_call, sum(duration) duration_outgoing_call
    from "CALL_HISTORY" sch
    where CALL_DIRECTION='O' AND (START_TIME BETWEEN '2022-01-01' AND '2022-03-01') AND (STATUS=3) group by user_id
  ) as outgoing_call
full join
  (select user_id, (select user_name from "USERS" where id=sch.user_id) user_name, count(id) num_incoming_call, sum(duration) duration_incoming_call
    from "CALL_HISTORY" sch
    where CALL_DIRECTION='I' AND (START_TIME BETWEEN '2022-01-01' AND '2022-03-01') AND (STATUS=3) group by user_id
  ) as incoming_call
on outgoing_call.user_name=incoming_call.user_name

结果集不是我想要的。我还尝试将查询作为“Right Join”、“Left Join”和“Full Join”，但没有得到我预期的结果。能不能写一个查询语句就可以看到预期的结果？

Answer 1

一切都比你想象的要简单得多。您只需要一个简单的连接和条件聚合，例如 sum(case when call_direction='I' then duration end).

看看这个：https://dbfiddle.uk/?rdbms=firebird_3.0&fiddle=1d9cbe0e617f89d8bf698b1a22d4bd76

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