我想迭代 JSON 并从 postgresql 转换成行

Question

基本上我想迭代 JSON 直到它从 table 开始的长度，但其余值保持不变直到当前 JSON 结束。我的Table格式是这样的

id	line	txndate	metadata	docnumber
363	[{"Id": "0", "Amount": 135000.0, "DetailType": "JournalEntryLineDetail", "Description": "Paid Office Rent Of Office", "JournalEntryLineDetail": {"AccountRef": {"name": "Rent or lease payments", "value": "57"}, "PostingType": "Debit"}}, {"Id": "1", "Amount": 135000.0, "DetailType": "JournalEntryLineDetail", "Description": "Paid Office Rent Of Office", "JournalEntryLineDetail": {"AccountRef": {"name": "Cash and cash equivalents:Bank", "value": "83"}, "PostingType": "Credit"}}]	2021-08-16 00:00:00.000000 +00:00	{"CreateTime": "2021-08-20T05:39:38.000000Z", "LastUpdatedTime": "2021-08-20T05:39:38.000000Z"}	332
610	[{"Id": "0", "Amount": 4138088.25, "DetailType": "JournalEntryLineDetail", "Description": "Deposit in Bank", "JournalEntryLineDetail": {"AccountRef": {"name": "Cash and cash equivalents:Bank", "value": "83"}, "PostingType": "Debit"}}, {"Id": "1", "Amount": 4138088.25, "DetailType": "JournalEntryLineDetail", "Description": "Deposit in Bank", "JournalEntryLineDetail": {"AccountRef": {"name": "Share capital", "value": "8"}, "PostingType": "Credit"}}, {"Id": "2", "DetailType": "DescriptionOnly", "Description": "Deposit in Bank"}]	2021-10-11 00:00:00.000000 +00:00	{"CreateTime": "2021-10-13T10:44:09.000000Z", "LastUpdatedTime": "2021-10-13T10:44:09.000000Z"}	560
381	[{"Id": "0", "Amount": 30000.0, "DetailType": "JournalEntryLineDetail", "Description": "Paid to Punkish", "JournalEntryLineDetail": {"AccountRef": {"name": "Advance Against Salary", "value": "103"}, "PostingType": "Debit"}}, {"Id": "1", "Amount": 30000.0, "DetailType": "JournalEntryLineDetail", "Description": "Paid to Punkish", "JournalEntryLineDetail": {"AccountRef": {"name": "Cash and cash equivalents:Bank", "value": "83"}, "PostingType": "Credit"}}]	2021-07-01 00:00:00.000000 +00:00	{"CreateTime": "2021-08-23T05:31:42.000000Z", "LastUpdatedTime": "2021-08-23T05:47:03.000000Z"}	521

但我想提取如下信息table

id	line_id	Amount	Description	name	value	posting_type	txndate	CreatedTime	LastUpdatedTime
363	0	13500	Paid Office Rent Of Office	Rent or lease payments	57	Debit	2021-08-16 00:00:00.000000 +00:00	2021-08-20T05:39:38.000000Z	2021-08-20T05:39:38.000000Z
363	1	13500	Paid Office Rent Of Office	Cash and cash equivalents:Bank	83	Cebit	2021-08-16 00:00:00.000000 +00:00	2021-08-20T05:39:38.000000Z	2021-08-20T05:39:38.000000Z
610	0	4138088.25	Deposit in Bank	Cash and cash equivalents:Bank	83	Debit	2021-10-11 00:00:00.000000 +00:00	2021-10-13T10:44:09.000000Z	2021-10-13T10:44:09.000000Z
610	1	4138088.25	..........	..	...	...	2021-10-11 00:00:00.000000 +00:00	2021-10-13T10:44:09.000000Z	2021-10-13T10:44:09.000000Z
610	2	4138088.25	..........	..	...	...	2021-10-11 00:00:00.000000 +00:00	2021-10-13T10:44:09.000000Z	2021-10-13T10:44:09.000000Z
610	3	4138088.25	..........	..	...	...	2021-10-11 00:00:00.000000 +00:00	2021-10-13T10:44:09.000000Z	2021-10-13T10:44:09.000000Z

我想将 JSON 列条目转换为行，但希望保留 id、txndate、CreatedTime 和 LastUpdatedTime 相同，直到 JSON 列的长度为 line 在我的例子中。

如果可能，请指导我解决方案。注意：我使用的是 Postgresql，line 列的数据类型是 jsonb

Answer 1

给你，你可以使用jsonb_array_elements函数将JSON的数组转换为行，然后在每一行上查询

Demo

select
  t.id,
  e.value ->> 'Id' as line_id,
  e.value ->> 'Amount' as amount,
  e.value ->> 'Description' as description,
  e.value -> 'JournalEntryLineDetail' -> 'AccountRef' ->> 'name' as name,
  e.value -> 'JournalEntryLineDetail' -> 'AccountRef' ->> 'value' as value,
  e.value -> 'JournalEntryLineDetail' ->> 'PostingType' as posting_type,
  t.txndate,
  t.metadata ->> 'CreateTime' as CreatedTime,
  t.metadata ->> 'LastUpdatedTime' as LastUpdatedTime
from
  test t
  cross join jsonb_array_elements(t.line) e

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