使用 yq 从 YAML 映射对象中删除某些字段

Question

我需要为 yaml 文件做一些棘手的事情，这是它之前的样子

之前

apiVersion: v1
items:
  - apiVersion: core.k8s.com/v1alpha1
    kind: Test
    metadata:
      creationTimestamp: '2022-02-097T19:511:11Z'
      finalizers:
        - cuv.ssf.com
      generation: 1
      name: bar
      namespace: foo
      resourceVersion: '12236'
      uid: 0117657e8
    spec:
      certificateIssuer:
        acme:
          email: myemail
      provider:
        credentials: dst
        type: foo
      domain: vst
      type: bar
    status:
      conditions:
        - lastTransitionTime: '2022-02-09T19:50:12Z'
          message: test
          observedGeneration: 1
          reason: Ready
          status: 'True'
          type: Ready
      lastOperation:
        description: test
        state: Succeeded
        type: Reconcile

https://codebeautify.org/yaml-validator/y22fe4943

我需要删除 metadata 部分下的所有字段，棘手的部分是只保留 name 和 namespace 除了完全删除 status 部分之外，它应该如下所示

之后

  apiVersion: v1
    items:
      - apiVersion: core.k8s.com/v1alpha1
        kind: Test
        metadata:
          name: bar
          namespace: foo
        spec:
          certificateIssuer:
            acme:
              email: myemail
          provider:
            credentials: dst
            type: foo
          domain: vst
          type: bar

link之后 https://codebeautify.org/yaml-validator/y220531ef

使用 yq (https://github.com/mikefarah/yq/) 版本 4.19.1

Answer 1

这应该在 https://github.com/kislyuk/yq (not https://github.com/mikefarah/yq 的实现中使用 yq 和 -y（或 -Y）标志：

yq -y '.items[] |= (del(.status) | .metadata |= {name, namespace})'

apiVersion: v1
items:
  - apiVersion: core.k8s.com/v1alpha1
    kind: Test
    metadata:
      name: bar
      namespace: foo
    spec:
      certificateIssuer:
        acme:
          email: myemail
      provider:
        credentials: dst
        type: foo
      domain: vst
      type: bar

Answer 2

使用 mikefarah/yq (aka Go yq), you could do something like below. Using del for deleting an entry and with_entries 选择已知字段

yq '.items[] |= (del(.status) | .metadata |= with_entries(select(.key == "name" or .key == "namespace")))' yaml

开始v4.18.1，eval标志是默认动作，所以e标志可以避免

使用 yq 从 YAML 映射对象中删除某些字段

Remove certain fields from a YAML map object using yq

yaml

yq