如何在单独的方法中删除重复操作？

Question

我的代码必须在 7 次尝试中猜测从 0 到 100 的隐藏数字。每次我需要再次调用相同的操作时。如何将这些操作移动到一个单独的方法中并从那里调用它们？

public class Main {
  public static void main(String[] args) throws IOException {
    int min = 0;
    int max = 100;
    int midrange = Math.round((min + max)/2);
    String strInput = "";
    Scanner scan = new Scanner(System.in);

    while (!strInput.equals("1")){
        System.out.println("Guess a number from 0 to 100: I'll guess it in 7 attempts! Enter 1 to continue:");
        strInput = scan.nextLine();
    }

    while (!strInput.equals("+") && !strInput.equals("-") && !strInput.equals("=")){
        System.out.println("Is this number greater than, less than or equal to " + midrange + "? " +
                "Enter '+', if it's greater, '-' if it's less and '=' if it's equal:");
        strInput = scan.nextLine();
    }

    if (strInput.equals("=")) System.out.println("Great! Thank you for the game.");
    else if (strInput.equals("+")){
        // reduce the range
        min = midrange;

        // find a new midrange
        midrange = Math.round((min + max)/2);
    } else if (strInput.equals("-")){
        max = midrange;
        midrange = Math.round((min + max)/2);
    }

    strInput = "";

    while (!strInput.equals("+") && !strInput.equals("-") && !strInput.equals("=")){
        System.out.println("Is this number greater than, less than or equal to " + midrange + "? ");
        strInput = scan.nextLine();
    }

    // ... and so on until the correct number is found.

  }
}

Answer 1

您不需要多个 while 循环。只需检查相等性并将 if-else-block 放入 while 循环。如果你猜对了数字就跳出循环。

public static void main(String[] args) throws IOException {

    int min = 0;
    int max = 100;
    int midrange = Math.round((min + max) / 2);
    String strInput = "";
    Scanner scan = new Scanner(System.in);

    System.out.println("Guess a number from 0 to 100: I'll guess it in 7 attempts! Enter 1 to continue:");
    strInput = scan.nextLine();

    while (!strInput.equals("=")) {
        System.out.println("Is this number greater than, less than or equal to " + midrange + "? " +
                "Enter '+', if it's greater, '-' if it's less and '=' if it's equal:");
        strInput = scan.nextLine();
        if (strInput.equals("=")) {
            System.out.println("Great! Thank you for the game.");
            break;
        } else if (strInput.equals("+")) {
            min = midrange;
            midrange = Math.round((min + max) / 2);
        } else if (strInput.equals("-")) {
            max = midrange;
            midrange = Math.round((min + max) / 2);
        }
    }
}

如何在单独的方法中删除重复操作？

How to remove repetitive operations in a separate method?

java

methods

refactoring

static

duplicates