Git 与脚本不同

Question

我正在尝试编写一个脚本，该脚本采用提交日志消息的正则表达式，然后显示所有提交的 git 差异。我的脚本中有以下内容：

#!/bin/sh
ARGV=("$@")
dir=$(pwd)
commits=($(git --work-tree ${dir} log --grep ${ARGV[0]} | grep -o 'commit .*$' | cut -f2 -d' '))
echo $(git --work-tree ${dir} log --grep ${ARGV[0]})
for i in ${commits[@]}
do
    echo "command: git diff ${i}"
    echo $(git diff ${i})
 done

当我运行 /path/to/script.sh <some-regex> 我得到以下输出：

command: git diff 806e5e76c0b20eabda3a14b1442168149ad30155

fatal: ambiguous argument '806e5e76c0b20eabda3a14b1442168149ad30155': unknown revision or path not in the working tree. Use '--' to separate paths from revisions, like this: 'git [...] -- [...]'

然而，当我运行输出实际命令时，一切正常。有什么想法吗？

Answer 1

a script which takes a regular expression for commit log messages then displays the git diff across all the commits

这不就可以了吗？

git log --patch --grep=<pattern>

explainshell.com - git log --patch --grep

Git 与脚本不同

Git diff from script

git

git-diff