Blaze 持久化 UpdatableEntityView 作为 spring 启动请求正文

Question

我正在尝试使用 blaze persistence UpdatableEntityView 作为带有 spring 引导的请求主体。以下是 UpdatableEntityView

的代码

@UpdatableEntityView
@EntityView(DealListing.class)
public interface DealListingUpdateView {
    @IdMapping
    Long getId();
    void setId(Long id);

    Instant getListedOn();
    void setListedOn(Instant listedOn);
}

以下是其余的控制器映射

@PutMapping("/deal-listings/sell/{id}")
    public void test(@PathVariable Long id, @RequestBody DealListingUpdateView dealListingUpdateView){
        dealListingService.testUpdate(id, dealListingUpdateView);
}

以下是 pom.xml 执行 blaze 持久性文档中指定的反序列化的依赖项

        <dependency>
            <groupId>com.blazebit</groupId>
            <artifactId>blaze-persistence-integration-jackson</artifactId>
            <scope>compile</scope>
        </dependency>

但是当我提交请求时出现以下错误

Type definition error: [simple type, class com.ilex.tradeservice.domain.view.blaze.DealListingUpdateView]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `com.ilex.tradeservice.domain.view.blaze.DealListingUpdateView` (no Creators, like default constructor, exist): abstract types either need to be mapped to concrete types, have custom deserializer, or contain additional type information\n at [Source: (PushbackInputStream); line: 1, column: 1]

Answer 1

如您在文档中所见，您将需要 Spring Data WebMvc 集成：https://persistence.blazebit.com/documentation/1.6/entity-view/manual/en_US/index.html#spring-data-webmvc-integration

您还必须使用 @EntityViewId("id")

额外注释您的控制器参数

@PutMapping("/deal-listings/sell/{id}")
public void test(@PathVariable Long id, @EntityViewId("id") @RequestBody DealListingUpdateView dealListingUpdateView){
        dealListingService.testUpdate(id, dealListingUpdateView);
}

Blaze 持久化 UpdatableEntityView 作为 spring 启动请求正文

Blaze persistence UpdatableEntityView as spring boot request body

spring-boot

blaze-persistence