Bash，变量的行包含子字符串？

Question

在尝试编写一个可靠的 bash 方法来检测由多行文本组成的变量是否包含子字符串（可能包含空格）时，我遇到了一些困难。编写了三个函数，我使用 BATS 框架为它们编写了一些测试。下面列出了它们失败的功能和附带的测试。

方法一

lines_contain_string() {
    local substring=""
    shift
    local lines=("$@")
    
    local found_substring="NOTFOUND"

    for i in "${lines[@]}"; do
        if [[ $i == *"$substring"* ]]; then
            echo "FOUND"
            local found_substring="FOUND"
        fi
    done

    if [ "$found_substring" == "NOTFOUND" ]; then
        echo "NOTFOUND"
    fi
}

测试失败：

EXAMPLE_LINES=$(cat <<-END
First line
second line 
third line 
sometoken
END
)

@test "Substring in first line is found in lines by lines_contain_string." {
    contained_substring="First line"
    
    actual_result=$(lines_contain_string "$contained_substring" "${EXAMPLE_LINES}")
    #actual_result=$(lines_contain_string_with_space "$contained_substring" "${EXAMPLE_LINES}")
    EXPECTED_OUTPUT="FOUND"
        
    assert_equal "$actual_result" "$EXPECTED_OUTPUT"
}

所以第一种方法没有捕获所有子字符串。

方法二

对于第二种方法：

lines_contain_string_with_space() {
    local substring=""
    local lines="$@"
    if [ "$lines" == "" ]; then
        echo "NOTFOUND"
    # shellcheck disable=SC2154
    elif [[ "$lines" =~ "$substring" ]]; then
        echo "FOUND"; 
    else
        echo "NOTFOUND";
    fi
}

这似乎 return 错误 positive/seems 总是 return “找到”，例如，在测试中：

EXAMPLE_LINES=$(cat <<-END
First line
second line 
third line 
sometoken
END
)

@test "lines_contain_string returns NOTFOUND on non-existing substring." {
    contained_substring="Non-existing-substring"
    
    #actual_result=$(lines_contain_string "$contained_substring" "${EXAMPLE_LINES}")
    actual_result=$(lines_contain_string_with_space "$contained_substring" "${EXAMPLE_LINES}")
    EXPECTED_OUTPUT="NOTFOUND"
        
    assert_equal "$actual_result" "$EXPECTED_OUTPUT"
}

方法三

此方法由choroba提供：

string_in_lines() {
    local substring=
    shift
    local lines=
    if [[ $lines = *"$substring"* ]] ; then
        echo FOUND
    else
        echo NOTFOUND
    fi
}

并用测试调用它：

@test "Substring in first line is found in lines by lines_contain_string." {
    contained_substring="First line"
    
    read -p "EXAMPLE_LINES=$EXAMPLE_LINES"

    #actual_result=$(lines_contain_string "$contained_substring" "${EXAMPLE_LINES}")
    #actual_result=$(lines_contain_string_with_space "$contained_substring" "${EXAMPLE_LINES}")
    actual_result=$(string_in_lines "$contained_substring" "${EXAMPLE_LINES}")
    EXPECTED_OUTPUT="FOUND"
        
    assert_equal "$actual_result" "$EXPECTED_OUTPUT"
}

产生输出：

 ✗ Substring in first line is found in lines by lines_contain_string.
   (from function `assert_equal' in file test/no_server_required/preserves_server/../../libs/bats-assert/src/assert_equal.bash, line 40,
    in test file test/no_server_required/preserves_server/test_parsing.bats, line 35)
     `assert_equal "$actual_result" "$EXPECTED_OUTPUT"' failed
   EXAMPLE_LINES=First line
   second line 
   third line 
   sometoken
   -- values do not equal --
   expected : FOUND
   actual   : NOTFOUND
   --

问题

如何根据由多行组成的传入变量是否包含可能包含空格的子字符串，在 bash 函数中回显“FOUND”/“NOTFOUND”？（并相应地进行测试。）

备注

由于我的测试在 choroba 提供的方法上也失败了，我认为成功的可能性很大，我预计我的测试功能不正确。我相应地更新了问题。

choroba 的评论建议反斜杠：`"${EXAMPLE_LINES}" 不正确。我测试了一下是不是不对，结果是不对。所以解决方案是将测试编写为：

@test "Substring in first line is found in lines by lines_contain_string." {
    contained_substring="First line"

    #actual_result=$(lines_contain_string "$contained_substring" "${EXAMPLE_LINES}")
    #actual_result=$(lines_contain_string_with_space "$contained_substring" "${EXAMPLE_LINES}")
    actual_result=$(string_in_lines "$contained_substring" "${EXAMPLE_LINES}")
    EXPECTED_OUTPUT="FOUND"
        
    assert_equal "$actual_result" "$EXPECTED_OUTPUT"
}

@test "lines_contain_string returns NOTFOUND on non-existing substring." {
    contained_substring="Non-existing-substring"
    
    #actual_result=$(lines_contain_string "$contained_substring" "${EXAMPLE_LINES}")
    #actual_result=$(lines_contain_string_with_space "$contained_substring" "${EXAMPLE_LINES}")
    actual_result=$(string_in_lines "$contained_substring" "${EXAMPLE_LINES}")
    EXPECTED_OUTPUT="NOTFOUND"
        
    assert_equal "$actual_result" "$EXPECTED_OUTPUT"
}

Answer 1

使用 = 和通配符模式。

string_in_lines() {
    local substring=
    shift
    local lines=
    if [[ $lines = *"$substring"* ]] ; then
        echo FOUND
    else
        echo NOTFOUND
    fi
}

Bash，变量的行包含子字符串？

Bash, lines of a variable contain substring?

string

bash

contains

line

bats-core

方法一

方法二

方法三

问题

备注