SQL 当出现多个日期但受频率计数限制时加入单个日期
SQL Joining with single dates when Multiple Dates occur but limited by a frequency count
在 SQL 中，我希望将两个 table 与一个 table 中的多个日期链接到另一个 table 中的一个日期，我希望通过一个 table 的频率。相反，我一直在获取所有频率的所有记录的总和。
我试过联接、where 子句和子查询，但总是出错。我最近被引导到 Dibble，并认为这是演示问题的最佳方式：
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=a9fec08a4ec5130c93da6ed663259da4
示例 table 是：
CREATE TABLE dbo.Action
(
ActionWeek date,
ActionYear int,
Region nvarchar(50),
Action nvarchar(50),
ActionAmount int,
Frequency int);
INSERT INTO Action values
('2019-01-01' , 2019, 'Wales', 'abc123', 123, 1),
('2019-03-10' , 2019, 'Wales', 'abc123', 132, 2),
('2019-06-01' , 2019, 'Wales', 'abc123', 153, 3),
('2020-01-11' , 2020, 'Wales', 'abc123', 123, 1),
('2019-01-01' , 2019, 'Australia', 'abd133', 723, 1),
('2019-08-01' , 2019, 'Australia', 'abd133', 763, 2),
('2020-04-01' , 2020, 'Australia', 'abd133', 823, 1),
('2019-01-01' , 2019, 'Mexico', 'cbc423', 3123, 1),
('2020-03-01' , 2020, 'Mexico', 'cbc423', 3223, 1),
('2020-05-01' , 2020, 'Mexico', 'cbc423', 3423, 2),
('2020-08-21' , 2020, 'Mexico', 'cbc423', 3623, 3),
('2021-01-01' , 2021, 'Mexico', 'cbc423', 3723, 1),
('2021-09-01' , 2021, 'Mexico', 'cbc423', 3823, 2)
-- Second Table
CREATE TABLE dbo.Response
(
ResponseYear int,
ResponseAction nvarchar(50),
ResponseDate date,
ResponseWeek date,
ResponseValue float,
);
INSERT INTO Response values
(2019, 'abc123', '2019-02-04', '2019-02-01', 50),
(2019, 'abc123', '2019-02-08', '2019-02-08', 25),
(2019, 'abc123', '2019-09-24', '2019-09-24', 100),
(2020, 'abc123', '2020-01-20', '2019-01-23', 5),
(2021, 'abc123', '2021-06-10', '2021-06-07', 3),
(2019, 'abd133', '2019-01-10', '2019-01-07', 15),
(2019, 'abd133', '2019-02-10', '2019-02-04', 25),
(2019, 'abd133', '2019-03-10', '2019-03-04', 35),
(2021, 'cbc423', '2021-01-13', '2021-01-11', 77)
期望的结果是：
A.ActionWeek / A.Action / A.Frequency / R.ResponseValue
2019-01-01 / abc123 / 1 / 75
2019-03-10 / abc123 / 2 / 0
2019-06-01 / abc123 / 3 / 100
2020-01-11 / abc123 / 1 / 8
2019-01-01 / abd133 / 1 / 75
2019-08-01 / abd133 / 2 / 0
2020-04-01 / abd133 / 1 / 0
2019-01-01 / cbc423 / 1 / 0
2020-03-01 / cbc423 / 1 / 0
2020-05-01 / cbc423 / 2 / 0
2020-08-21 / cbc423 / 3 / 0
2021-01-01 / cbc423 / 1 / 77
2021-09-01 / cbc423 / 2 / 0
如果您还有其他问题，请告诉我？
我试过这个：
SELECT A.ActionWeek, A.Action, A.Frequency
, (SELECT SUM(R.ResponseValue)
FROM Response R2
JOIN Action A2 ON R2.Action and A2.Action
WHERE A.Frequency = A2.Frequency
) AS ResponseValue
FROM Action A
JOIN Response R ON A.Action = R.ResponseAction
GROUP BY A.ActionWeek, A.Action, A.Frequency
ORDER BY A.ActionWeek, A.Action, A.Frequency
我完全不知道频率与此有什么关系，你似乎不需要它，因为很容易获得下一个日期作为加入测试
with cte as
(select a.actionweek fromweek,a.action,a.frequency,
lead(a.actionweek) over (partition by a.action order by a.actionweek) toweek
from [action] a)
select cte.fromweek,cte.toweek, cte.action,cte.frequency,r.responseweek,r.responsevalue
--sum(r.responsevalue)
from cte
left join response r on cte.action = r.ResponseAction and ResponseWeek between cte.fromweek and cte.toweek;
结果
fromweek toweek action frequency responseweek responsevalue
---------- ---------- -------------------------------------------------- ----------- ------------ ----------------------
2019-01-01 2019-03-10 abc123 1 2019-02-01 50
2019-01-01 2019-03-10 abc123 1 2019-02-08 25
2019-01-01 2019-03-10 abc123 1 2019-01-23 5
2019-03-10 2019-06-01 abc123 2 NULL NULL
2019-06-01 2020-01-11 abc123 3 2019-09-24 100
2020-01-11 NULL abc123 1 NULL NULL
2019-01-01 2019-08-01 abd133 1 2019-01-07 15
2019-01-01 2019-08-01 abd133 1 2019-02-04 25
2019-01-01 2019-08-01 abd133 1 2019-03-04 35
2019-08-01 2020-04-01 abd133 2 NULL NULL
2020-04-01 NULL abd133 1 NULL NULL
2019-01-01 2020-03-01 cbc423 1 NULL NULL
2020-03-01 2020-05-01 cbc423 1 NULL NULL
2020-05-01 2020-08-21 cbc423 2 NULL NULL
2020-08-21 2021-01-01 cbc423 3 NULL NULL
2021-01-01 2021-09-01 cbc423 1 2021-01-11 77
2021-09-01 NULL cbc423 2 NULL NULL
(17 row(s) affected)
将其更改为总和
with cte as
(select a.actionweek fromweek,a.action,a.frequency,
lead(a.actionweek) over (partition by a.action order by a.actionweek) toweek
from [action] a)
select cte.fromweek,cte.action,cte.frequency,
sum(r.responsevalue)
from cte
left join response r on cte.action = r.ResponseAction and ResponseWeek between cte.fromweek and cte.toweek
group by cte.action,cte.fromweek,cte.frequency
order by cte.action,cte.fromweek,cte.frequency
fromweek action frequency
---------- -------------------------------------------------- ----------- ----------------------
2019-01-01 abc123 1 80
2019-03-10 abc123 2 NULL
2019-06-01 abc123 3 100
2020-01-11 abc123 1 NULL
2019-01-01 abd133 1 75
2019-08-01 abd133 2 NULL
2020-04-01 abd133 1 NULL
2019-01-01 cbc423 1 NULL
2020-03-01 cbc423 1 NULL
2020-05-01 cbc423 2 NULL
2020-08-21 cbc423 3 NULL
2021-01-01 cbc423 1 77
2021-09-01 cbc423 2 NULL
Warning: Null value is eliminated by an aggregate or other SET operation.
(13 row(s) affected)
在 SQL 中，我希望将两个 table 与一个 table 中的多个日期链接到另一个 table 中的一个日期，我希望通过一个 table 的频率。相反，我一直在获取所有频率的所有记录的总和。
我试过联接、where 子句和子查询，但总是出错。我最近被引导到 Dibble，并认为这是演示问题的最佳方式：
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=a9fec08a4ec5130c93da6ed663259da4
示例 table 是：
CREATE TABLE dbo.Action
(
ActionWeek date,
ActionYear int,
Region nvarchar(50),
Action nvarchar(50),
ActionAmount int,
Frequency int);
INSERT INTO Action values
('2019-01-01' , 2019, 'Wales', 'abc123', 123, 1),
('2019-03-10' , 2019, 'Wales', 'abc123', 132, 2),
('2019-06-01' , 2019, 'Wales', 'abc123', 153, 3),
('2020-01-11' , 2020, 'Wales', 'abc123', 123, 1),
('2019-01-01' , 2019, 'Australia', 'abd133', 723, 1),
('2019-08-01' , 2019, 'Australia', 'abd133', 763, 2),
('2020-04-01' , 2020, 'Australia', 'abd133', 823, 1),
('2019-01-01' , 2019, 'Mexico', 'cbc423', 3123, 1),
('2020-03-01' , 2020, 'Mexico', 'cbc423', 3223, 1),
('2020-05-01' , 2020, 'Mexico', 'cbc423', 3423, 2),
('2020-08-21' , 2020, 'Mexico', 'cbc423', 3623, 3),
('2021-01-01' , 2021, 'Mexico', 'cbc423', 3723, 1),
('2021-09-01' , 2021, 'Mexico', 'cbc423', 3823, 2)
-- Second Table
CREATE TABLE dbo.Response
(
ResponseYear int,
ResponseAction nvarchar(50),
ResponseDate date,
ResponseWeek date,
ResponseValue float,
);
INSERT INTO Response values
(2019, 'abc123', '2019-02-04', '2019-02-01', 50),
(2019, 'abc123', '2019-02-08', '2019-02-08', 25),
(2019, 'abc123', '2019-09-24', '2019-09-24', 100),
(2020, 'abc123', '2020-01-20', '2019-01-23', 5),
(2021, 'abc123', '2021-06-10', '2021-06-07', 3),
(2019, 'abd133', '2019-01-10', '2019-01-07', 15),
(2019, 'abd133', '2019-02-10', '2019-02-04', 25),
(2019, 'abd133', '2019-03-10', '2019-03-04', 35),
(2021, 'cbc423', '2021-01-13', '2021-01-11', 77)
期望的结果是：
A.ActionWeek / A.Action / A.Frequency / R.ResponseValue
2019-01-01 / abc123 / 1 / 75
2019-03-10 / abc123 / 2 / 0
2019-06-01 / abc123 / 3 / 100
2020-01-11 / abc123 / 1 / 8
2019-01-01 / abd133 / 1 / 75
2019-08-01 / abd133 / 2 / 0
2020-04-01 / abd133 / 1 / 0
2019-01-01 / cbc423 / 1 / 0
2020-03-01 / cbc423 / 1 / 0
2020-05-01 / cbc423 / 2 / 0
2020-08-21 / cbc423 / 3 / 0
2021-01-01 / cbc423 / 1 / 77
2021-09-01 / cbc423 / 2 / 0
如果您还有其他问题，请告诉我？
我试过这个：
SELECT A.ActionWeek, A.Action, A.Frequency
, (SELECT SUM(R.ResponseValue)
FROM Response R2
JOIN Action A2 ON R2.Action and A2.Action
WHERE A.Frequency = A2.Frequency
) AS ResponseValue
FROM Action A
JOIN Response R ON A.Action = R.ResponseAction
GROUP BY A.ActionWeek, A.Action, A.Frequency
ORDER BY A.ActionWeek, A.Action, A.Frequency
我完全不知道频率与此有什么关系，你似乎不需要它，因为很容易获得下一个日期作为加入测试
with cte as
(select a.actionweek fromweek,a.action,a.frequency,
lead(a.actionweek) over (partition by a.action order by a.actionweek) toweek
from [action] a)
select cte.fromweek,cte.toweek, cte.action,cte.frequency,r.responseweek,r.responsevalue
--sum(r.responsevalue)
from cte
left join response r on cte.action = r.ResponseAction and ResponseWeek between cte.fromweek and cte.toweek;
结果
fromweek toweek action frequency responseweek responsevalue
---------- ---------- -------------------------------------------------- ----------- ------------ ----------------------
2019-01-01 2019-03-10 abc123 1 2019-02-01 50
2019-01-01 2019-03-10 abc123 1 2019-02-08 25
2019-01-01 2019-03-10 abc123 1 2019-01-23 5
2019-03-10 2019-06-01 abc123 2 NULL NULL
2019-06-01 2020-01-11 abc123 3 2019-09-24 100
2020-01-11 NULL abc123 1 NULL NULL
2019-01-01 2019-08-01 abd133 1 2019-01-07 15
2019-01-01 2019-08-01 abd133 1 2019-02-04 25
2019-01-01 2019-08-01 abd133 1 2019-03-04 35
2019-08-01 2020-04-01 abd133 2 NULL NULL
2020-04-01 NULL abd133 1 NULL NULL
2019-01-01 2020-03-01 cbc423 1 NULL NULL
2020-03-01 2020-05-01 cbc423 1 NULL NULL
2020-05-01 2020-08-21 cbc423 2 NULL NULL
2020-08-21 2021-01-01 cbc423 3 NULL NULL
2021-01-01 2021-09-01 cbc423 1 2021-01-11 77
2021-09-01 NULL cbc423 2 NULL NULL
(17 row(s) affected)
将其更改为总和
with cte as
(select a.actionweek fromweek,a.action,a.frequency,
lead(a.actionweek) over (partition by a.action order by a.actionweek) toweek
from [action] a)
select cte.fromweek,cte.action,cte.frequency,
sum(r.responsevalue)
from cte
left join response r on cte.action = r.ResponseAction and ResponseWeek between cte.fromweek and cte.toweek
group by cte.action,cte.fromweek,cte.frequency
order by cte.action,cte.fromweek,cte.frequency
fromweek action frequency
---------- -------------------------------------------------- ----------- ----------------------
2019-01-01 abc123 1 80
2019-03-10 abc123 2 NULL
2019-06-01 abc123 3 100
2020-01-11 abc123 1 NULL
2019-01-01 abd133 1 75
2019-08-01 abd133 2 NULL
2020-04-01 abd133 1 NULL
2019-01-01 cbc423 1 NULL
2020-03-01 cbc423 1 NULL
2020-05-01 cbc423 2 NULL
2020-08-21 cbc423 3 NULL
2021-01-01 cbc423 1 77
2021-09-01 cbc423 2 NULL
Warning: Null value is eliminated by an aggregate or other SET operation.
(13 row(s) affected)