数组中嵌套对象值的总和
total sum of nested object value in array
如何计算给定数组中所有 stationuserAmount 值的总和
"staions": [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": "190"
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": "280"
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": "280"
}
]
}
]
我尝试使用 map 和 reduce 数组值来查找给定数组的总和。
1) const salesuserTotalCount = this.state.staions.map(items => ({
users: items.stationuser.reduce((a, b) => {return
a.stationuserAmount+b.stationuserAmount}
)}))
2) const salesuserTotalCount = this.state.staions.map(items => ({
...items,
users: items.stationuser.map(stationitems
=>stationitems.stationuserAmount).reduce((a, c)
=> { return a + c })}))
你可以在reduce里面做reduce
const stations = [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": 190
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": 280
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": 280
}
]
}
]
console.log(stations.reduce((acc, curr)=>{
return acc+curr.stationuser.reduce((a,c)=>a+c.stationuserAmount,0)
},0));
您可以使用嵌套地图轻松完成。
const data = { "stations": [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": 190
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": 280
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": 280
}
]
}
]
}
let sum = 0
data.stations.map(station => {
station.stationuser.map(user => sum += user.stationuserAmount)
})
console.log(sum)
如何计算给定数组中所有 stationuserAmount 值的总和
"staions": [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": "190"
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": "280"
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": "280"
}
]
}
]
我尝试使用 map 和 reduce 数组值来查找给定数组的总和。
1) const salesuserTotalCount = this.state.staions.map(items => ({
users: items.stationuser.reduce((a, b) => {return
a.stationuserAmount+b.stationuserAmount}
)}))
2) const salesuserTotalCount = this.state.staions.map(items => ({
...items,
users: items.stationuser.map(stationitems
=>stationitems.stationuserAmount).reduce((a, c)
=> { return a + c })}))
你可以在reduce里面做reduce
const stations = [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": 190
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": 280
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": 280
}
]
}
]
console.log(stations.reduce((acc, curr)=>{
return acc+curr.stationuser.reduce((a,c)=>a+c.stationuserAmount,0)
},0));
您可以使用嵌套地图轻松完成。
const data = { "stations": [
{
"name": "Guwahati",
"stationuser": [
{
"name": "Suranjan Dey",
"stationuserAmount": 190
}
]
},
{
"name": "Bhubaneshwar",
"stationuser": [
{
"name": "Soubhagya Behera",
"stationuserAmount": 280
},
{
"name": "Om Prakash Sahoo",
"stationuserAmount": 280
}
]
}
]
}
let sum = 0
data.stations.map(station => {
station.stationuser.map(user => sum += user.stationuserAmount)
})
console.log(sum)