我如何在 objective c 的句子中找到单词的位置范围？

Question

如何在 objective c 的句子中查找特定单词的位置范围？

假设我有以下 NSString

NSString *stringOfHashTags = "mr#hello Mr.#hello"

我正在使用

NSString word=@"hello";
    NSRange termsRange = [stringOfHashTags rangeOfString:[word substringFromIndex:[word rangeOfString:@"#"].location]];

查找以 # 开头的单词的位置，但如果该单词在句子中出现两次或多次，它只会 returns 第一个位置。任何帮助表示赞赏。

Answer 1

您可以使用enumerateSubstringsInRange（搜索和阅读文档始终是起点）。

简单示例：

NSString *aString = @"mr#hello Mr.#hello";
NSString *word = @"hello";
[aString enumerateSubstringsInRange:NSMakeRange(0, [aString length])
                            options:NSStringEnumerationByWords | NSStringEnumerationLocalized
                         usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){
    if ([substring rangeOfString:word options:NSCaseInsensitiveSearch].location != NSNotFound) {
        /* do whatever */;
        NSLog(@"found at: %@ / %@", [NSValue valueWithRange:substringRange], [NSValue valueWithRange:enclosingRange]);
    }
}];

调试控制台输出：

proj[64417:6900139] found at: NSRange: {3, 5} / NSRange: {3, 6}
proj[64417:6900139] found at: NSRange: {13, 5} / NSRange: {13, 5}

编辑

如果要查找字符串中所有以 # 开头的单词例如：

"this #is a #test of #88 including embedded #tags such as Mr.#tags. #Is that #what you're looking #for?"

与查找一个词的多次出现（如您的问题）相反，您可能希望使用正则表达式。

另一个快速、简单的例子：

NSString *searchedString = @"this #is a #test of #88 including embedded #tags such as Mr.#tags. #Is that #what you're looking #for?";
NSRange searchedRange = NSMakeRange(0, [searchedString length]);

// searching for any Word that begins with #
NSString *pattern = @"\#\w+";
NSError  *error = nil;

NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern: pattern options:0 error:&error];
if (error) {
    NSLog(@"Could not create regex!!!");
    return;
}

NSArray *matches = [regex matchesInString:searchedString options:0 range: searchedRange];
for (NSTextCheckingResult *match in matches) {
    NSString *matchText = [searchedString substringWithRange:[match range]];
    NSLog(@"match: %@", matchText);
}

调试控制台输出：

proj[66898:6935236] match: #is
proj[66898:6935236] match: #test
proj[66898:6935236] match: #88
proj[66898:6935236] match: #tags
proj[66898:6935236] match: #tags
proj[66898:6935236] match: #Is
proj[66898:6935236] match: #what
proj[66898:6935236] match: #for

编辑 2

您的第二条评论确实应该是新的 post，因为这是一个完全不同的问题（关于 RegEx 语法）。

但是，为了让您上路...

NSString *searchedString = @"These #tags, with #various& #excluded! #chars. And #other@ formats #88 including #emojis or # even middle#tags";
NSRange searchedRange = NSMakeRange(0, [searchedString length]);

// searching for any Sub-String that
//  begins with #
//  ends with a character from an "end" set
//
// Notes:
//  \s means any white-space
//  \ needs to be escaped, e.g. \ or \s
//  you probably want to add more "end" chars

NSString *endChars = @"\s\?!@;:%^&*().,";
NSString *pattern = [NSString stringWithFormat:@"\#[^%@]+", endChars];
NSError  *error = nil;

NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern: pattern options:0 error:&error];
if (error) {
    NSLog(@"Could not create regex!!!");
    return;
}

NSArray *matches = [regex matchesInString:searchedString options:0 range: searchedRange];
for (NSTextCheckingResult *match in matches) {
    NSString *matchText = [searchedString substringWithRange:[match range]];
    NSLog(@"match: %@", matchText);
}

调试控制台输出：

proj[73128:7009059] match: #tags
proj[73128:7009059] match: #various
proj[73128:7009059] match: #excluded
proj[73128:7009059] match: #chars
proj[73128:7009059] match: #other
proj[73128:7009059] match: #88
proj[73128:7009059] match: #emojis
proj[73128:7009059] match: #
proj[73128:7009059] match: #tags

我如何在 objective c 的句子中找到单词的位置范围？

How do i find range of locations of a word in a sentence in objective c?

objective-c

ios