如何使用 Selenium 自动接受来自 java 应用程序的 cookie 弹出窗口

Question

应用程序将加载系统默认浏览器，加载一个特殊的网站，然后自动登录

import java.awt.Desktop;
import java.io.IOException;
import java.net.URI;
import java.net.URISyntaxException;

import org.openqa.selenium.WebDriver;
import org.openqa.selenium.chrome.ChromeDriver;

public class theurl {
public static void main(String[] args) {
    String url = "http://www.playok.com/en/spades/";
    if(Desktop.isDesktopSupported()){
        Desktop desktop = Desktop.getDesktop();
        try {
            desktop.browse(new URI(url));
        } catch (IOException | URISyntaxException e) {
            e.printStackTrace();
        }
    }else{
        Runtime runtime = Runtime.getRuntime();
        try {
            runtime.exec("xdg-open " + url);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

但在尝试登录之前，首先应该自动接受 cookie；有没有一种简单的方法而不是使用外部库？如果没有，哪个图书馆可以完成这项工作

我试过这段代码，但没有帮助：

WebDriver Driver = new ChromeDriver();
Driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
String url = "http://www.playok.com/en/spades/";
Driver.get(url);
Driver.findElement(By.id("cookie_action_close_header")).click();
System.out.println("completed");

Answer 1

至 on the element you need to induce for the and you can use either of the following ：

cssSelector:

Driver.get("http://www.playok.com/en/spades/");
new WebDriverWait(Driver, 20).until(ExpectedConditions.elementToBeClickable(By.cssSelector("button.ckbut.but0"))).click();

xpath:

Driver.get("http://www.playok.com/en/spades/");
new WebDriverWait(Driver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//button[@class='ckbut but0' and text()='ACCEPT']"))).click();

如何使用 Selenium 自动接受来自 java 应用程序的 cookie 弹出窗口

How to automate accept cookies pop-up from java app using Selenium

java

selenium

xpath

css-selectors

webdriverwait