如何 Select 结点 table 中任何给定 ID 的所有可能的不同相关 "two-ways" 值？

Question

table TBL_IN "输入文档详细信息 table"

IID	IDate	ISubject
I-225
I-300
I-410

tableTBL_OUT“OUT文档详细信息table”

OID	ODate	OSubject
O-20
O-35

table TBL_INOUT "IN OUT 文档连接点 table"

IOID	IID	OID
1	I-225	O-20
2	I-225	O-35
3	I-300	O-35
4	I-410	O-20

问题是如何在 oracle sql 或从结点 table 访问查询中得到以下查询结果？

查询QRY_INOUT_Related“Select任何给定 ID 的所有可能相关的“双向”值”

ID	IO_Related
O-20	I-225,I410,O-35,I-300

ID	IO_Related
I-300	O-35,I-225,O-20,I-410

我希望我尽可能地阐明了这个想法。

Answer 1

在 Oracle 中，您似乎想要一个分层查询，它通过 IID 或 OID 找到所有不同的连接，然后想要聚合：

SELECT id,
       LISTAGG(value, ',') WITHIN GROUP (ORDER BY value) AS io_related
FROM   (
  SELECT DISTINCT id, value
  FROM   (
    SELECT CONNECT_BY_ROOT oid AS id,
           iid,
           oid
    FROM   tbl_inout
    START WITH oid = 'O-20'
    CONNECT BY NOCYCLE
       PRIOR oid = oid
    OR PRIOR iid = iid
  )
  UNPIVOT(value FOR key IN (iid, oid))
  WHERE id <> value
)
GROUP BY id

输出：

ID IO_RELATED

O-20 I-225,I-300,I-410,O-35

和

SELECT id,
       LISTAGG(value, ',') WITHIN GROUP (ORDER BY value) AS io_related
FROM   (
  SELECT DISTINCT id, value
  FROM   (
    SELECT CONNECT_BY_ROOT iid AS id,
           iid,
           oid
    FROM   tbl_inout
    START WITH iid = 'I-300'
    CONNECT BY NOCYCLE
       PRIOR oid = oid
    OR PRIOR iid = iid
  )
  UNPIVOT(value FOR key IN (iid, oid))
  WHERE id <> value
)
GROUP BY id

输出：

ID IO_RELATED

I-300 I-225,I-410,O-20,O-35

db<>fiddle here

如何 Select 结点 table 中任何给定 ID 的所有可能的不同相关 "two-ways" 值？

How to Select all possible distinct related "two-ways" values for any given ID from a junction table?

sql

oracle

ms-access

plsql

junction-table