Neo4j

Question

我正在使用 neo4j 和 cypher 并试图找出我的查询速度慢的原因。

这是我标记为已弃用的原始查询：

match (h:Hierarchy)-[r:PARENT_OF*1..4]->(s:SoldTo)
where  h.id='0100001709' 
    and all(x in r 
        where x.to>=date('2022-02-15') 
        and x.from <= date('2022-02-15') 
        and x.hvkorg='S000'
        and x.hvtweg='D1'
)
and s.loevm=""
and s.aufsd=""    
and s.cassd=""
and s.faksd=""
and s.lifsd=""
and s.sperr=""
and s.sperz=""
r>eturn distinct  h.id,s.id

这个工作正常并且 returns 结果很快：Started streaming 60 records after 1 ms and completed after 17 ms. 但是 neo4j 给出以下警告：

This feature is deprecated and will be removed in future versions. Binding relationships to a list in a variable length pattern is deprecated. (Binding a variable length relationship pattern to a variable ('r') is deprecated and will be unsupported in a future version. The recommended way is to bind the whole path to a variable, then extract the relationships: MATCH p = (...)-[...]-(...) WITH *, relationships(p) AS r)

现在，我试过了：

match p=(h:Hierarchy)-[:PARENT_OF*1..4]->(s:SoldTo)
with *, relationships(p) as r
where  h.id='0100001709' 
and all(x in r 
    where x.to>=date('2022-02-15') 
        and x.from <= date('2022-02-15') 
        and x.hvkorg='S000'
        and x.hvtweg='D1'
)
and s.loevm=""
and s.aufsd=""    
and s.cassd=""
and s.faksd=""
and s.lifsd=""
and s.sperr=""
and s.sperz=""
return distinct  h.id,s.id

但是，这很慢：Started streaming 60 records in less than 1 ms and completed after 36931 ms.

17 毫秒与 36931 毫秒

你们有任何关于使用 relationships() 来加快速度的建议吗？

Answer 1

查询中存在拼写错误。不要在第一行进行扫描，而是放置 where 子句（在第 3 行到第 2 行中找到）。这将在 h 处启用一个起始节点，并使您的查询更快。

Original:
match p=(h:Hierarchy)-[:PARENT_OF*1..4]->(s:SoldTo)
with *, relationships(p) as r
where  h.id='0100001709' 

Updated:
match p=(h:Hierarchy)-[:PARENT_OF*1..4]->(s:SoldTo)
where  h.id='0100001709' 
with h, s, relationships(p) as r
...
...
return distinct  h.id,s.id

Neo4j - 密码 - 变长模式慢

Neo4j - cypher - variable length pattern slow

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cypher

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