我想扩展我的程序，以便在用户猜对数字、猜得太高或太低时显示。我的代码有什么问题？

Question

def dice_game():
    print ("Welcome to my dice game")
import random
your_name = input ("Please enter your name:")
your_lucky_number = int(input ("Please select a lucky number between 1 and 6:"))
print (your_name,"'s lucky number was:", your_lucky_number)
#initialize computer number
computer_die_roll = random.randint(1,6)
print ("The computer rolled: ", computer_die_roll)

if your_lucky_number == computer_die_roll:
    print("You guessed correct, well done!")
    break
elif your_lucky_number < computer_die_roll:
    print("You guessed too low!")
    else:
        print("You guessed too high!")

Answer 1

您的代码存在几个问题，大致按严重程度排序：

else 块的缩进错误。缩进它，使其与 if 和 elif 语句处于同一级别。
您不能在 if 块中使用 break。这将创建一个 SyntaxError，因此将其删除。
您没有验证您的数字输入并盲目地将其转换为 int，当您通过抛出 ValueError.
你的代码看起来很乱。请关注standard formatting conventions。有一个工具可以自动修复这个问题，叫做 autopep8.

我想扩展我的程序，以便在用户猜对数字、猜得太高或太低时显示。我的代码有什么问题？

I want to extend my program so that it displays if the user guessed the correct number, guessed too high or too low. What's wrong with my code?

python-3.x

numbers

dice