带有可执行示例的多个复选框选择中的简单问题。有没有自动识别多个复选框的方法？

Question

是否有自动识别多个 selected 复选框的方法？我不想手动创建多个 selection 组合。我想得到那个：

1/3 复选框：如果我单独 select 第一个或第三个框，我会在文本框中打印“确定”
2/3 复选框：如果我同时 select 第一个和第三个，我会在文本框中打印“ok”。但是只打印了一个“ok”，而不是两个“ok ok”（所以两个复选框对应一个 ok）
我不想在文本框中打印第二个复选框，因为我故意在上面写错了。

问题出在这个函数上。可能AND（或OR）不是我需要的，我猜，我不知道：

def aaa():
    if Checkbutton1.get() and Checkbutton2.get() and Checkbutton3.get():
        textbox.insert("end", "Ok")

#I also tried to write: if Button1_func() and Button2_func() and Button3_func():

我想解决方案是为每种类型的多个 selection 案例创建其他条件，但我认为有一种更自动和更好的方法，无需创建 selection 有条件的案例，因为我将不得不添加几十个其他复选框，情况会变得复杂。

重要提示：请不要讽刺 True 和 False，因为 5 + 3 = 8 只是一个简单的示例，用于理解复选框的逻辑，我将不得不对其应用其他不同的代码。保持 return True 和 False 不变，不更改函数。

谁能帮我看看正确的代码？谢谢

import sqlite3
from tkinter import *
from tkinter import ttk
import tkinter as tk
import tkinter.messagebox
from tkinter import messagebox

root = tk.Tk()
root.geometry("600x600")
root.configure(bg='white')

Checkbutton1 = IntVar()
Checkbutton2 = IntVar()
Checkbutton3 = IntVar()

#CHECKBOX'S FUNCTIONS
def Button1_func():
    if 5 + 3 == 8:
        return True
    else:
        return False

def Button2_func():
    if 5 + 3 == 7:
        return True
    else:
        return False

def Button3_func():
    if 5 + 3 == 8:
        return True
    else:
        return False

#CHECKBOX
Button1 = Checkbutton(root, text = "Checkbox 1", variable = Checkbutton1, onvalue = 1, offvalue = 0, height = 1,
                      bg="white", foreground='black', activebackground="white", command=Button1_func)
Button1.place(x=10, y=36)

Button2 = Checkbutton(root, text = "Checkbox 2", variable = Checkbutton2, onvalue = 1, offvalue = 0, height = 1,
                      bg="white", foreground='black', activebackground="white", command=Button2_func)
Button2.place(x=10, y=66)

Button3 = Checkbutton(root, text = "Checkbox 3", variable = Checkbutton3, onvalue = 1, offvalue = 0, height = 1,
                      bg="white", foreground='black', activebackground="white", command=Button3_func)
Button3.place(x=10, y=146)

#BUTTON FUNCTION
def aaa():
    if Checkbutton1.get() and Checkbutton2.get() and Checkbutton3.get():
        textbox.insert("end", "Ok")

    #I also tried to write: if Button1_func () and Button2_func () and Button3_func ():

#TEXTOBOX
textbox = tk.Text(root, width=33, height=10, font=('helvetic', 12))
textbox.place(x=30, y=220)

#BUTTON
button = tk.Button(root, text="Ok", command= lambda: [aaa()])
button.pack()


root.mainloop()

更新在代码中还有这个，我用它来保存和加载复选框：

chk_lst = []
chk_lst.extend([Checkbutton1,Checkbutton2, Checkbutton3])

Answer 1

已编辑以澄清问题

因为每个 Checkbutton 都有一个与之关联的独特功能，您将需要手动定义这些。现在，我已经用函数代替了。

您实际上不需要将函数传递给复选按钮，因为它们仅在您单击 Button 时才被评估。相反，您可以更改 aaa，以便它为勾选的 Checkbuttons 创建一个函数结果列表。如果这些 return False 中的任何一个，都不要打印“OK”。但是如果他们都return True，打印“OK”

import tkinter as tk

root = tk.Tk()
root.geometry("600x600")

# How many checkboxes you want
buttons = 5
button_eval = [0 for i in range(buttons)]

# If your functions are unique for each checkbox, you will need to define them here
def foo():
    return True
def bar():
    return False
my_functions = [foo, bar, foo, bar, foo] # You need to have 5 functions in this case for this to work

# Creating variables, buttons etc
x = [10, 10, 10, 10, 10]
y = [36, 66, 96, 126, 156]
checkbuttons_vars = [tk.IntVar() for _ in range(buttons)]
checkbuttons = [tk.Checkbutton(root, text=f"Checkbox {i+1}", variable=checkbuttons_vars[i], onvalue=1, offvalue=0) for i in range(buttons)]
for i, box in enumerate(checkbuttons):
    box.place(x=x[i],y=y[i])

#BUTTON FUNCTION
def aaa():
    function_results = [function() for i, function in enumerate(my_functions) if checkbuttons_vars[i].get()]
    textbox.delete(1.0, "end")
    if False not in function_results:
        textbox.insert(1.0, "Ok")

#TEXTOBOX
textbox = tk.Text(root, width=33, height=10, font=('helvetic', 12))
textbox.pack()

#BUTTON
button = tk.Button(root, text="Ok", command=aaa)
button.pack()

root.mainloop()

Answer 2

您可以使用 set 来存储基于这些复选按钮状态的函数引用。然后在aaa()里面执行set里面的所有函数，判断是否在文本框中输入OK：

def clicked(flag, func):
    if flag:
        funclist.add(func)
    else:
        funclist.remove(func)

funclist = set()

#CHECKBOX
Button1 = tk.Checkbutton(root, text = "Checkbox 1", variable = Checkbutton1, onvalue = 1, offvalue = 0, height = 1,
                         bg="white", foreground='black', activebackground="white",
                         command=lambda: clicked(Checkbutton1.get(), Button1_func))
Button1.place(x=10, y=36)

Button2 = tk.Checkbutton(root, text = "Checkbox 2", variable = Checkbutton2, onvalue = 1, offvalue = 0, height = 1,
                         bg="white", foreground='black', activebackground="white",
                         command=lambda: clicked(Checkbutton2.get(), Button2_func))
Button2.place(x=10, y=66)

Button3 = tk.Checkbutton(root, text = "Checkbox 3", variable = Checkbutton3, onvalue = 1, offvalue = 0, height = 1,
                         bg="white", foreground='black', activebackground="white",
                         command=lambda: clicked(Checkbutton3.get(), Button3_func))
Button3.place(x=10, y=146)

#BUTTON FUNCTION
def aaa():
    # if need to clear the text box, uncomment below line
    #textbox.delete("1.0", "end")
    if funclist and all(func() for func in funclist):
        textbox.insert("end", "Ok")

带有可执行示例的多个复选框选择中的简单问题。有没有自动识别多个复选框的方法？

Simple problem in multiple checkbox selection with executable example. Is there automatic way to recognize the plurality multiple selected checkboxes?

python

checkbox

tkinter

python-3.x