减少数组数组，按日期将数据连接到周数据并对值求和

Question

所以我有一组奇特的数据：

data: [
  ['2022-01-17T16:29:24', 30], // these below would aggregate to 210
  ['2022-01-17T17:37:24', 30],
  ['2022-01-17T17:41:40', 30],
  ['2022-01-17T17:41:48', 30],
  ['2022-01-21T12:50:18', 30],
  ['2022-01-21T12:50:18', 30],
  ['2022-01-21T12:50:29', 30],        
  ['2022-01-12T12:50:18', 30], // these below would aggregate to 90
  ['2022-01-12T12:50:18', 30],
  ['2022-01-12T12:50:29', 30]
]

我需要将其缩减为周数据集。我会将日期转换为一周的开始以获取周数据 moment(day).startOf('isoWeek')，然后将类似日期的数据合并并将其减少为单个条目。

最终结果如下：

data: [
  ['2022-01-17T00:00:00', 210],
  ['2022-01-10T00:00:00', 90]
]

但我正在寻找如何使用 .reduce() 或任何其他更现代的解决方案的建议，这些解决方案将在大型集上表现出色。现在我已经为此嵌套了 for 循环（除了看起来很糟糕）可能表现很差，因为它在同一个数组上迭代多次。一个要求是 moment 应该用于日期操作，请尽量避免 Date 对象。

现在我有这样的东西：

mergeDataToWeek(data: any[]) {
  let reducedArrays = [];
  for (let arr of data) {
    if (moment(arr[0]).isValid() && arr[1] > 0) {
      arr[0] = moment(arr[0]).startOf('isoWeek').toISOString(true);
      if (!reducedArrays.some(reduced => reduced[0] == (arr[0]))) {
        reducedArrays.push(arr);
      } else {
        let target = reducedArrays.find(reduced => reduced[0] == arr[0]);
        target[1] += arr[1];
      }
    }
  }
  console.log(reducedArrays);
  return reducedArrays;
}

Answer 1

我正在尝试使用 reduce 解决它，但结果将是一个对象。像这样：

const moment = require("moment")
var x = [
    ['2022-01-17T16:29:24', 30], 
    ['2022-01-17T17:37:24', 30],
    ['2022-01-17T17:41:40', 30],
    ['2022-01-17T17:41:48', 30],
    ['2022-01-21T12:50:18', 30],
    ['2022-01-21T12:50:18', 30],
    ['2022-01-21T12:50:29', 30],        
    ['2022-01-12T12:50:18', 30], 
    ['2022-01-12T12:50:18', 30],
    ['2022-01-12T12:50:29', 30]
  ]

// solution
var y = x.reduce((a,b) => {
    const key = moment(b[0]).startOf("isoWeek").format()
    a[key] = a[key]? a[key]+b[1]: b[1]
    return a
}, {})

console.log(y)

输出：

{ 
  "2022-01-17T00:00:00+07:00": 210,
  "2022-01-10T00:00:00+07:00": 90 
}

但如果您希望它像您的数组一样，我们可以通过以下方式转换它：

var z = Object.keys(y).map(i => [i,y[i]])

// OR THIS -- Thanks to @ghybs
var z = Object.entries(y)

console.log(z)

输出：

[
  [ '2022-01-17T00:00:00+07:00', 210 ],
  [ '2022-01-10T00:00:00+07:00', 90 ]
]

虽然这不是最好的解决方案，但我认为它比嵌套循环更具可读性。

Answer 2

运行代码

let x = [
  ['2022-01-17T16:29:24', 30],
  ['2022-01-17T17:37:24', 30],
  ['2022-01-17T17:41:40', 30],
  ['2022-01-17T17:41:48', 30],
  ['2022-01-21T12:50:18', 30],
  ['2022-01-21T12:50:18', 30],
  ['2022-01-21T12:50:29', 30],
  ['2022-01-12T12:50:18', 30],
  ['2022-01-12T12:50:18', 30],
  ['2022-01-12T12:50:29', 30]
]

// solution
const groupedTotal = x.reduce((a, b) => {
  const key = moment(b[0]).startOf("isoWeek").format()
  a[key] = a[key] ? a[key] + b[1] : b[1]
  return a
}, {});

const totals = Object.entries(groupedTotal);

console.log("Grouped Total:", groupedTotal, "\n Totals:", totals);

<script src="https://unpkg.com/moment@2.29.1/moment.js"></script>

注意：- 来自@Rizal Ardhi Rahmadani 的代码...

减少数组数组，按日期将数据连接到周数据并对值求和

Reduce array of arrays, concat data by dates to week data and sum the values

javascript

momentjs

运行代码

减少数组数组，按日期将数据连接到周数据并对值求和

Reduce array of arrays, concat data by dates to week data and sum the values

javascript

momentjs

运行 代码

运行代码