从 ARN 中提取资源 ID

Question

我在 AWS 文档中看到 ARN 格式是：

arn:partition:service:region:account-id:resource-id
arn:partition:service:region:account-id:resource-type/resource-id
arn:partition:service:region:account-id:resource-type:resource-id

我正在尝试从 ARN 中获取 resource-id。

下面的代码可以工作，但是很难看...

我正在寻找改进方法：

func GetResourceNameFromARN(roleARN string) string {
    if parsedARN, err := arn.Parse(roleARN); err == nil {
        return parsedARN.Resource
    }

    return ""
}

func extractResourceId(arn string) string {
    resource := GetResourceNameFromARN(arn)
    switch len(strings.Split(resource, "/")) {
    case 1:
        switch len(strings.Split(resource, ":")) {
        case 2:
            return strings.Split(resource, ":")[1]
        }

    case 2:
        return strings.Split(resource, "/")[1]

    }
    return resource
}

Answer 1

我建议使用一个简单的正则表达式：

package main

import (
    "fmt"
    "regexp"
)

func main() {
    // Compile the expression once, usually at init time.
    // Use raw strings to avoid having to quote the backslashes.
    var validID = regexp.MustCompile(`[^:/]*$`)

    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-id"))
    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type/resource-id"))
    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type:resource-id"))
}

观看演示 here

从 ARN 中提取资源 ID

Extract resource-id from ARN

go

aws-sdk

aws-sdk-go