FOR XML EXPLICIT：创建多个结果行

Question

我想在一个语句中创建多个 XML Files/Result 行。

我有：

with invoices as (
    select '1' HID, 'Test1' HData, '1' PID, 'Pos1' PData union
    select '1' HID, 'Test1' HData, '2' PID, 'Pos2' PData union
    select '1' HID, 'Test1' HData, '3' PID, 'Pos3' PData union
    select '2' HID, 'Test2' HData, '4' PID, 'Pos1' PData union
    select '2' HID, 'Test2' HData, '5' PID, 'Pos2' PData union
    select '2' HID, 'Test2' HData, '6' PID, 'Pos3' PData
)
select
    case when GROUPING_ID(PID) = 0 then 4
        when GROUPING_ID(HData) = 0 then 3
        when GROUPING_ID(HID) = 0 then 2
        else 1 end tag,
    case when GROUPING_ID(PID) = 0 then 2
        when GROUPING_ID(HData) = 0 then 2
        when GROUPING_ID(HID) = 0 then 1
        else null end parent,
    null [Root!1],
    HID [Invoice!2!HID],
    HData [Header!3!HData!Element],
    PID [Pos!4!PID],
    PData [Pos!4!PData!Element]
from invoices
group by grouping sets ((), (HID), (HID, HData), (HID, HData, PID, PData))
order by HID, HData, PID
for xml explicit, type;

我得到的：

我想要的：

这可能吗？怎么做到的？

Answer 1

您只需为每个不同的 HID:

生成 XML 输出

;WITH invoices as (
    select '1' HID, 'Test1' HData, '1' PID, 'Pos1' PData union
    select '1' HID, 'Test1' HData, '2' PID, 'Pos2' PData union
    select '1' HID, 'Test1' HData, '3' PID, 'Pos3' PData union
    select '2' HID, 'Test2' HData, '4' PID, 'Pos1' PData union
    select '2' HID, 'Test2' HData, '5' PID, 'Pos2' PData union
    select '2' HID, 'Test2' HData, '6' PID, 'Pos3' PData
)
SELECT 
   XMLColumn = (
      select
         case when GROUPING_ID(PID) = 0 then 4
              when GROUPING_ID(HData) = 0 then 3
              when GROUPING_ID(HID) = 0 then 2
              else 1 
         end tag,
         case when GROUPING_ID(PID) = 0 then 2
              when GROUPING_ID(HData) = 0 then 2
              when GROUPING_ID(HID) = 0 then 1
              else null 
         end parent,
         null [Root!1],
         HID [Invoice!2!HID],
         HData [Header!3!HData!Element],
         PID [Pos!4!PID],
         PData [Pos!4!PData!Element]
      from invoices
      WHERE i.HID = HID
      group by grouping sets ((), (HID), (HID, HData), (HID, HData, PID, PData))
      order by HID, HData, PID
      for xml explicit, type
   )
FROM invoices i
GROUP BY HID

FOR XML EXPLICIT：创建多个结果行

FOR XML EXPLICIT: Create multiple result rows

sql-server

for-xml-explicit