如何过滤 spark 数据框中的结构数组?
How to filter a struct array in a spark dataframe?
我有以下代码和输出。
import org.apache.spark.sql.functions.{collect_list, struct}
import sqlContext.implicits._
val df = Seq(
("john", "tomato", 1.99),
("john", "carrot", 0.45),
("bill", "apple", 0.99),
("john", "banana", 1.29),
("bill", "taco", 2.59)
).toDF("name", "food", "price")
df.groupBy($"name")
.agg(collect_list(struct($"food", $"price")).as("foods"))
.show(false)
df.printSchema
输出和架构:
+----+---------------------------------------------+
|name|foods |
+----+---------------------------------------------+
|john|[[tomato,1.99], [carrot,0.45], [banana,1.29]]|
|bill|[[apple,0.99], [taco,2.59]] |
+----+---------------------------------------------+
root
|-- name: string (nullable = true)
|-- foods: array (nullable = false)
| |-- element: struct (containsNull = false)
| | |-- food: string (nullable = true)
| | |-- price: double (nullable = false)
我想根据 df("foods.price") > 1.00 进行过滤。我如何过滤它以获得下面的输出?
+----+---------------------------------------------+
|name|foods |
+----+---------------------------------------------+
|john|[[banana,1.29], [tomato,1.99]] |
|bill|[[[taco,2.59]] |
+----+---------------------------------------------+
我已尝试 df.filter($"foods.food" > 1.00)
,但这不起作用,因为我遇到了错误。还有什么我可以尝试的吗?
您正在尝试对数组应用过滤器,因此它会抛出错误,因为语法有误。您可以先对价格应用过滤器,然后根据需要进行转换。
val cf = df.filter("price > 1.0").groupBy($"name").agg(collect_list(struct($"food", $"price")).as("foods")
我有以下代码和输出。
import org.apache.spark.sql.functions.{collect_list, struct}
import sqlContext.implicits._
val df = Seq(
("john", "tomato", 1.99),
("john", "carrot", 0.45),
("bill", "apple", 0.99),
("john", "banana", 1.29),
("bill", "taco", 2.59)
).toDF("name", "food", "price")
df.groupBy($"name")
.agg(collect_list(struct($"food", $"price")).as("foods"))
.show(false)
df.printSchema
输出和架构:
+----+---------------------------------------------+
|name|foods |
+----+---------------------------------------------+
|john|[[tomato,1.99], [carrot,0.45], [banana,1.29]]|
|bill|[[apple,0.99], [taco,2.59]] |
+----+---------------------------------------------+
root
|-- name: string (nullable = true)
|-- foods: array (nullable = false)
| |-- element: struct (containsNull = false)
| | |-- food: string (nullable = true)
| | |-- price: double (nullable = false)
我想根据 df("foods.price") > 1.00 进行过滤。我如何过滤它以获得下面的输出?
+----+---------------------------------------------+
|name|foods |
+----+---------------------------------------------+
|john|[[banana,1.29], [tomato,1.99]] |
|bill|[[[taco,2.59]] |
+----+---------------------------------------------+
我已尝试 df.filter($"foods.food" > 1.00)
,但这不起作用,因为我遇到了错误。还有什么我可以尝试的吗?
您正在尝试对数组应用过滤器,因此它会抛出错误,因为语法有误。您可以先对价格应用过滤器,然后根据需要进行转换。
val cf = df.filter("price > 1.0").groupBy($"name").agg(collect_list(struct($"food", $"price")).as("foods")