BigQuery - UNNEST 多维数组
BigQuery - UNNEST with a multidimensional array
我需要取消嵌套包含多个项目的多维数组。
我的数据如下所示(两行):
此 table 中的每个订单都有一个 fulfillments
列,它是一个多维数组。
fulfilments
有多个 line_items
。有些订单只有有1个line_items,有些订单有多个line_items.
我的目标是从每个 line_items
中获取每个产品名称和数量,然后执行 运行 sum/tally.
这是 fulfillments
列数据的 JSON 导出:
"{
"fulfillments": [{
"value": {
"id": "6575674745",
"tracking_number": null,
"line_items": [{
"value": {
"properties": [{
"value": {
"name": "shipping_interval_unit_type",
"value": "Months"
}
}, {
"value": {
"name": "shipping_interval_frequency",
"value": "1"
}
}, {
"value": {
"name": "ch_item_id",
"value": "77321530"
}
}],
"product_id": "4790985097351",
"total_discount_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"sku": “10101”,
"name": “Product1”,
"variant_id": "33433213108359",
"quantity": "1",
"taxable": "true",
"total_discount": "0",
"title": "Product1 Title",
"price_set": {
"shop_money": {
"amount": "12.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "12.00",
"currency_code": "USD"
}
},
"product_exists": "true"
}
}],
"service": "manual",
"tracking_urls": []
}
}, {
"value": {
"tracking_url": null,
"id": "3555531128967",
"tracking_company": null,
"tracking_number": null,
"name": "#3129472402.2",
"tracking_numbers": [],
"line_items": [{
"value": {
"properties": [{
"value": {
"name": "shipping_interval_frequency",
"value": "1"
}
}, {
"value": {
"name": "shipping_interval_unit_type",
"value": "Months"
}
}, {
"value": {
"name": "ch_item_id",
"value": "77321529"
}
}],
"product_id": "5216409780359",
"total_discount_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"sku": "9005",
"name": “Product2”,
"quantity": "1",
"title": “Product2 Title”,
"price_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"product_exists": "true"
}
}],
"service": "manual",
"tracking_urls": []
}
}]
}"
SELECT
fulfillments[ safe_OFFSET (0)].value.line_items[ safe_OFFSET (0)].value.name AS name,
fulfillments[ safe_OFFSET (0)].value.line_items[ safe_OFFSET (0)].value.quantity AS quantity
FROM
`mydatabase`
如果订单在 line_items
中有多个数组,则不理想
当我不知道每个数组有多大时如何取消嵌套多维数组?
SELECT
*
FROM
`mydatabase`,
UNNEST(fulfillments) as a
只给我另一个要展平的数组
鉴于您的情况,您可以尝试使用此查询来解除 line_items
与产品名称和数量的嵌套:
SELECT
line_items.value.name,
line_items.value.quantity,
line_items.value.product_id
from `mydatabase`,
unnest(fulfillments) fulfillments,
unnest(fulfillments.value.line_items) line_items
输出:
我需要取消嵌套包含多个项目的多维数组。
我的数据如下所示(两行):
此 table 中的每个订单都有一个 fulfillments
列,它是一个多维数组。
fulfilments
有多个 line_items
。有些订单只有有1个line_items,有些订单有多个line_items.
我的目标是从每个 line_items
中获取每个产品名称和数量,然后执行 运行 sum/tally.
这是 fulfillments
列数据的 JSON 导出:
"{
"fulfillments": [{
"value": {
"id": "6575674745",
"tracking_number": null,
"line_items": [{
"value": {
"properties": [{
"value": {
"name": "shipping_interval_unit_type",
"value": "Months"
}
}, {
"value": {
"name": "shipping_interval_frequency",
"value": "1"
}
}, {
"value": {
"name": "ch_item_id",
"value": "77321530"
}
}],
"product_id": "4790985097351",
"total_discount_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"sku": “10101”,
"name": “Product1”,
"variant_id": "33433213108359",
"quantity": "1",
"taxable": "true",
"total_discount": "0",
"title": "Product1 Title",
"price_set": {
"shop_money": {
"amount": "12.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "12.00",
"currency_code": "USD"
}
},
"product_exists": "true"
}
}],
"service": "manual",
"tracking_urls": []
}
}, {
"value": {
"tracking_url": null,
"id": "3555531128967",
"tracking_company": null,
"tracking_number": null,
"name": "#3129472402.2",
"tracking_numbers": [],
"line_items": [{
"value": {
"properties": [{
"value": {
"name": "shipping_interval_frequency",
"value": "1"
}
}, {
"value": {
"name": "shipping_interval_unit_type",
"value": "Months"
}
}, {
"value": {
"name": "ch_item_id",
"value": "77321529"
}
}],
"product_id": "5216409780359",
"total_discount_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"sku": "9005",
"name": “Product2”,
"quantity": "1",
"title": “Product2 Title”,
"price_set": {
"shop_money": {
"amount": "0.00",
"currency_code": "USD"
},
"presentment_money": {
"amount": "0.00",
"currency_code": "USD"
}
},
"product_exists": "true"
}
}],
"service": "manual",
"tracking_urls": []
}
}]
}"
SELECT
fulfillments[ safe_OFFSET (0)].value.line_items[ safe_OFFSET (0)].value.name AS name,
fulfillments[ safe_OFFSET (0)].value.line_items[ safe_OFFSET (0)].value.quantity AS quantity
FROM
`mydatabase`
如果订单在 line_items
当我不知道每个数组有多大时如何取消嵌套多维数组?
SELECT
*
FROM
`mydatabase`,
UNNEST(fulfillments) as a
只给我另一个要展平的数组
鉴于您的情况,您可以尝试使用此查询来解除 line_items
与产品名称和数量的嵌套:
SELECT
line_items.value.name,
line_items.value.quantity,
line_items.value.product_id
from `mydatabase`,
unnest(fulfillments) fulfillments,
unnest(fulfillments.value.line_items) line_items
输出: