是否可以同时显示新旧页面？

Question

我正在尝试为平滑状态构建这样的效果：http://tympanus.net/Development/PageTransitions/，特别是 "room" 过渡。

我无法尝试同时显示两个页面 - 我希望新内容将旧内容推出屏幕。

后面有很多代码……一切正常，但它要等到旧内容离开屏幕后才开始添加新内容

$(function(){
  'use strict';
  var options = {
    prefetch: true,
    cacheLength: 10,
    onStart: {
      duration: 500, // Duration of our animation
      render: function ($container) {
        // scroll up
        $("html, body").animate({ scrollTop: "0px" });
        var element = $('.row', $container);

        // do animations
        $(element).animate({opacity : 0}, {
            duration: 500,
            easing: "linear",
            step: function(number, tween) {
                number = 1 - number;
                var element = document.getElementsByClassName('row')[0];
                element.style.transform = "translateX(-" + 45*number + "%) rotateY(" + 90*number + "deg)";
            }
        });
      }
    },
    onReady: {
      duration: 500,
      render: function ($container, $newContent) {

        // Inject the new content
        $container.html($newContent);
        $container.css({overflow : 'hidden'});
        // do animations
        var element = document.getElementById($container[0].id).getElementsByClassName('row')[0];
        element.style.opacity = 0;
        $(element).animate({opacity : 1}, {
            duration: 500,
            step: function(number, tween) {
                number = 1 - number;
                var element = document.getElementsByClassName('row')[0];
                element.style.transform = "translateX(" + 45*number + "%) rotateY(-" + 90*number + "deg)";
            }
        }); 

      }
    }
  },
  smoothState = $('#main').smoothState(options).data('smoothState');
});

虽然将 onStart 持续时间更改为比动画持续时间短会奏效，但它只是将动画剪短，留下空白屏幕。

我知道 $container 用于两者，但我相信我可以使用 $container.clone(); 解决这个问题，以便在旧内容离开页面时保留它。

我的问题：除了等待 onStart 完成之外，还有其他方法可以访问 $newContent 吗？

注意：CSS 动画会出现相同的行为 - 它们在 onStart 结束时终止。

Answer 1

是的。诀窍是使用 setTimeout(,0) 到运行动画。为了简单起见，我最终将动画移动到 CSS class。由于内容重复（facebook、youtube 等），这在长页面上可能会滞后

它立即从 onStart 处理程序 returns 开始，但是运行动画一直持续到结束。准备就绪时调用onReady并启动入口动画。

[...]
onStart: {
  duration: 0,
  render: function ($container) {
    $('#tempWrapper').remove(); //if we have the temp wrapper, kill it now.
    $("html, body").animate({ scrollTop: "0px" });

    //make a duplicate container for animation...
    var $newContainer = $container.clone();
    $newContainer.attr("id", "tempWrapper");
    $newContainer.css({position:'absolute', top:$container.offset().top, width:$container.css("width")});
    $container.css({height:$container.css("height")});
    $container.empty(); //empty the old content so that it takes up 0 space
    $container.before($newContainer); // and immediately add the duplicate back on
    $('.row').removeClass('entering'); // just in case we have the class still
    var element = $('.row', $newContainer);
    setTimeout(callAnimation(element, true), 0); //start the animation
  }
},
onReady: {
  duration: 0,
  render: function ($container, $newContent) {
    // Inject the new content

    $container.html($newContent);

    // do animations
    var element = document.getElementById($container[0].id).getElementsByClassName('row')[0];

    callAnimation(element);
  }
}
[...]

function callAnimation(element, exiting) {
    if (!exiting) {
        $(element).addClass("entering");
    } else {
        $(element).addClass('exiting');
    }
}

Answer 2

希望你仍然需要它。我就是这样实现的：

$(function () {
    //'use strict';
    var $page = $('.m-scene'),
      options = {
          debug: true,
          onStart: {
              duration: 0,
              render: function ($container) {

                  $('.m-page.temp').remove(); //make sure we don't have more than two `pages` at a time
                  $('#move').removeClass('slideup'); //remove old animation; #move is the wrapper for original and injected content
                  $container.find('.m-page').addClass('temp'); //mark original content for removal
              }
          },
          onReady: {
              duration: 50, //prevents flickering of content 
              render: function ($container, $newContent) {
                  $('#move').append($newContent.find('.m-page')); //select only stuff you actually need injected
              }
          },
          onAfter: function ($container, $newContent) {
                var target = $('#move');
                animate(target); //it's animation time!
          }
      },
      smoothState = $page.smoothState(options).data('smoothState');
});

function animate(target) {
    target.addClass('slideup'); //add animation class
}

是否可以同时显示新旧页面？

Is it possible to show both the new and old pages simultaneously?

ajax

jquery

smoothstate.js