如何提取左括号和右括号之间的内容？

Question

我试图将一个字符串拆分为一个文本内容数组，每个文本内容都存在于 [@ 和 ] 分隔符中。只允许匹配 [@ 和 ] 之间的字符。提供类似 ...

的字符串

const stringA = '[@Mary James], [@Jennifer John] and [@Johnny Lever[@Patricia Robert] are present in the meeting and [@Jerry[@Jeffery Roger] is absent.'

...预期结果如下...

[
  'Mary James',
  'Jennifer John',
  'Patricia Robert',
  'Jeffery Roger'
]

可以使用导致预期结果的任何逻辑。

自我搜索解决方案提出了以下应用正则表达式...

stringA.match(/(?<=\[@)[^\]]*(?=\])/g);

但结果不符合要求，因为数组具有以下项目...

[
  'Mary James',
  'Jennifer John',
  'Johnny Lever[@Patricia Robert',
  'Jerry[@Jeffery Roger'
]

Answer 1

关闭，只是缺少 [ 的排除：

stringA.match(/(?<=\[@)[^\[\]]*(?=\])/g);
//                       ^^ exclude '[' as well as ']'

Answer 2

OP 的正则表达式在否定字符 class 中没有左括号，因此将 OP 的 /(?<=\[@)[^\]]*(?=\])/g 更改为 (?<=\[@)[^\[\]]*(?=\]) 已经解决了大多数环境下的 OP 问题 not including safari browsers due to the lookbehind which is not supported.

基于正则表达式的解决方案 ... /\[@(?<content>[^\[\]]+)\]/g ... with a named capture group ...

const sampleText = '[@Mary James], [@Jennifer John] and [@Johnny Lever[@Patricia Robert] are present in the meeting and [@Jerry[@Jeffery Roger] is absent.'

// see ... [https://regex101.com/r/v234aT/1]
const regXCapture = /\[@(?<content>[^\[\]]+)\]/g;

console.log(
  Array.from(
    sampleText.matchAll(regXCapture)
  ).map(
    ({ groups: { content } }) => content
  )
);

如何提取左括号和右括号之间的内容？

How to extract content in between an opening and a closing bracket?

javascript

regex

match

lookbehind

capture-group