如何按日期获取 SUM 而不会丢失依赖于求和实例的计算

Question

代码：

SELECT occurred_at, 
       SUM(CASE WHEN activity_name = 'create' THEN 1 ELSE 0 END) AS has_create, 
       SUM(CASE WHEN activity_name = 'Resolve' THEN 1 ELSE 0 END) AS has_resolve
FROM  Activity_Data_Table$
WHERE (occurred_at > CURRENT_TIMESTAMP - 31)
  AND (activity_name IN ('create', 'Resolve'))
GROUP BY session_id, occurred_at
HAVING (MAX(CASE WHEN activity_name = 'create' THEN 1 ELSE 0 END) <> 0)

尝试确定每天在同一会话中创建和解决的工单百分比。工单在创建之前无法解决。时间无关紧要，前提是它们在同一 'session' 中。票证绝对可以在一个会话中创建并在另一个会话中解决。还有其他状态，它们无关紧要。不关心是否解决了某些问题，而是来自不同的会话。因此，完成的结果将包含一个额外的列，其中包含以下数据的百分比 has_resolve/has_create 在每日级别。

上面的当前输出：

Answer 1

像这样：

WITH dat
AS
(
SELECT occurred_at, 
       SUM(CASE WHEN activity_name = 'create' THEN 1 ELSE 0 END) AS has_create, 
       SUM(CASE WHEN activity_name = 'Resolve' THEN 1 ELSE 0 END) AS has_resolve
FROM  Activity_Data_Table$
WHERE (occurred_at > CURRENT_TIMESTAMP - 31)
  AND (activity_name IN ('create', 'Resolve'))
GROUP BY session_id, occurred_at
HAVING (MAX(CASE WHEN activity_name = 'create' THEN 1 ELSE 0 END) <> 0)
)
SELECT occurred_at, SUM(CASE WHEN has_create + has_resolve = 2 THEN 1 ELSE 0 END) * 1.0 / COUNT(*) AS pct_resolved_in_same_session
FROM dat
GROUP BY occurred_at;

如何按日期获取 SUM 而不会丢失依赖于求和实例的计算

How do I get SUM by date without losing a calculation that relies on summing instance

sql

sum

calc