试图理解以工厂和基于函数的混合技术为特征的对象组合模式
Trying to understand an object composition pattern which features a factory and a function based mixin technique
我正在尝试了解 JavaScript 中基于函数的组合的行为。
const Animal = (name) => {
let properties = { name };
return ({
get name() { return properties.name },
set name(newName) { properties.name = newName },
breathe: function() {console.log(`${this.name} breathes!`); }
})
}
const aquaticKind = (animal) => ({
swim: () => console.log(`${animal.name} swims`)
})
const walkingKind = (animal, noOfLegs) => {
const properties = { noOfLegs }
return ({
get noOfLegs() { return properties.noOfLegs },
set noOfLegs(n) { properties.noOfLegs = n; },
walk: () => console.log(`${animal.name} walks with ${properties.noOfLegs} legs`)
})
}
const egglayingKind = (animal) => ({
layEgg: () => console.log(`${animal.name} laid an egg`)
})
const Crocodile = (name) => {
const info = Animal(name);
return Object.assign(info,
walkingKind(info, 4),
aquaticKind(info),
egglayingKind(info)
);
}
const snooty = Crocodile('snooty');
snooty.breathe();
snooty.swim();
snooty.walk();
snooty.name = "coolie";
snooty.noOfLegs = 23 // I expected this to get update to 23
snooty.swim();
snooty.walk();
snooty.layEgg();
如果您 运行 上面的代码,您会看到 noOfLegs
永远不会更新,而 name
会更新。我似乎无法解决这个问题。我们如何让 noOfLegs
也得到更新?
MDN Documentation for object.assign 向您展示如何复制“accessors”
这是按预期工作的代码 - completeAssign
函数完全基于 link
中的代码
const completeAssign = (target, ...sources) => {
sources.forEach(source => {
const descriptors = Object.keys(source).reduce((descriptors, key) => {
descriptors[key] = Object.getOwnPropertyDescriptor(source, key);
return descriptors;
}, {});
Object.getOwnPropertySymbols(source).forEach(sym => {
const descriptor = Object.getOwnPropertyDescriptor(source, sym);
if (descriptor.enumerable) {
descriptors[sym] = descriptor;
}
});
Object.defineProperties(target, descriptors);
});
return target;
};
const Animal = (name) => {
const properties = { name };
return ({
get name() { return properties.name },
set name(newName) { properties.name = newName },
breathe () { console.log(`${this.name} breathes!`); }
})
}
const aquaticKind = (animal) => ({
swim: () => console.log(`${animal.name} swims`)
});
const walkingKind = (animal, noOfLegs) => {
const properties = { noOfLegs };
return ({
get noOfLegs() { return properties.noOfLegs },
set noOfLegs(n) { properties.noOfLegs = n; },
walk: () => console.log(`${animal.name} walks with ${properties.noOfLegs} legs`)
})
}
const egglayingKind = (animal) => ({
layEgg: () => console.log(`${animal.name} laid an egg`)
})
const Crocodile = (name) => {
const info = Animal(name);
return completeAssign(info,
walkingKind(info, 4),
aquaticKind(info),
egglayingKind(info)
);
}
const snooty = Crocodile('snooty');
snooty.breathe();
snooty.swim();
snooty.walk();
snooty.name = "coolie";
snooty.noOfLegs = 23;
snooty.swim();
snooty.walk();
snooty.layEgg();
我正在尝试了解 JavaScript 中基于函数的组合的行为。
const Animal = (name) => {
let properties = { name };
return ({
get name() { return properties.name },
set name(newName) { properties.name = newName },
breathe: function() {console.log(`${this.name} breathes!`); }
})
}
const aquaticKind = (animal) => ({
swim: () => console.log(`${animal.name} swims`)
})
const walkingKind = (animal, noOfLegs) => {
const properties = { noOfLegs }
return ({
get noOfLegs() { return properties.noOfLegs },
set noOfLegs(n) { properties.noOfLegs = n; },
walk: () => console.log(`${animal.name} walks with ${properties.noOfLegs} legs`)
})
}
const egglayingKind = (animal) => ({
layEgg: () => console.log(`${animal.name} laid an egg`)
})
const Crocodile = (name) => {
const info = Animal(name);
return Object.assign(info,
walkingKind(info, 4),
aquaticKind(info),
egglayingKind(info)
);
}
const snooty = Crocodile('snooty');
snooty.breathe();
snooty.swim();
snooty.walk();
snooty.name = "coolie";
snooty.noOfLegs = 23 // I expected this to get update to 23
snooty.swim();
snooty.walk();
snooty.layEgg();
如果您 运行 上面的代码,您会看到 noOfLegs
永远不会更新,而 name
会更新。我似乎无法解决这个问题。我们如何让 noOfLegs
也得到更新?
MDN Documentation for object.assign 向您展示如何复制“accessors”
这是按预期工作的代码 - completeAssign
函数完全基于 link
const completeAssign = (target, ...sources) => {
sources.forEach(source => {
const descriptors = Object.keys(source).reduce((descriptors, key) => {
descriptors[key] = Object.getOwnPropertyDescriptor(source, key);
return descriptors;
}, {});
Object.getOwnPropertySymbols(source).forEach(sym => {
const descriptor = Object.getOwnPropertyDescriptor(source, sym);
if (descriptor.enumerable) {
descriptors[sym] = descriptor;
}
});
Object.defineProperties(target, descriptors);
});
return target;
};
const Animal = (name) => {
const properties = { name };
return ({
get name() { return properties.name },
set name(newName) { properties.name = newName },
breathe () { console.log(`${this.name} breathes!`); }
})
}
const aquaticKind = (animal) => ({
swim: () => console.log(`${animal.name} swims`)
});
const walkingKind = (animal, noOfLegs) => {
const properties = { noOfLegs };
return ({
get noOfLegs() { return properties.noOfLegs },
set noOfLegs(n) { properties.noOfLegs = n; },
walk: () => console.log(`${animal.name} walks with ${properties.noOfLegs} legs`)
})
}
const egglayingKind = (animal) => ({
layEgg: () => console.log(`${animal.name} laid an egg`)
})
const Crocodile = (name) => {
const info = Animal(name);
return completeAssign(info,
walkingKind(info, 4),
aquaticKind(info),
egglayingKind(info)
);
}
const snooty = Crocodile('snooty');
snooty.breathe();
snooty.swim();
snooty.walk();
snooty.name = "coolie";
snooty.noOfLegs = 23;
snooty.swim();
snooty.walk();
snooty.layEgg();