Angular 正则表达式拆分字符串 1x asd..... 2x asd

Question

我正在尝试将字符串拆分为 [0-9]+ [xX] | [0-9]+[xX]，字符串示例：

10 x source 4 50° on booms (2 downstage left and right, 2 upstage left and right) 2x festoons (mentioned above) 4x 1kx Fresnel backlight in L712 4x SL 15/32 (3x L443, 4x R119) – all four of which are specifically focused specials 1x Edison bulb suspended from grid

我想在 angular 中使用管道将文本分成单独的行，以显示如下：

10 x source 4 50° on booms (2 downstage left and right, 2 upstage left and right)
2x festoons (mentioned above)
4x 1kx Fresnel backlight in L712
4x SL 15/32 (3x L443, 4x R119) – all four of which are specifically focused specials
1x Edison bulb suspended from grid

我尝试使用以下正则表达式，但它在正则表达式中包含了下一个 1x。

/([0-9]+[xX] [a-zA-z].*)(?:([0-9]+[xX]))/gm

Output: 10x source 4 50° on booms (2 downstage left and right, 2 upstage left and right) 2x festoons (mentioned above) 4x 1kx Fresnel backlight in L712 4x SL 15/32 (3x L443, 4x R119) – all four of which are specifically focused specials 1x

我也希望能够添加第一句中提到的选项来检查两种情况。

1x asd....
1 x asd....

然后我将使用 Angular 中的正则表达式拆分字符串。

Answer 1

你可以使用

/\d+\s*x\b(?:\([^()]*\)|[^()])*?(?=\d+x|$)/gi

见regex demo。详情:

\d+ - 一位或多位数字
\s* - 零个或多个空格
x\b - x 和单词边界
(?:$[^()]*$|[^()])*? - ( 的零个或多个（但尽可能少）序列 + ( 和 ) + [= 以外的零个或多个字符19=] 或除 ( 和 )
(?=\d+x|$) - 与紧跟一个或多个数字和 x 或字符串末尾的位置匹配的正前瞻。

查看 JavaScript 演示：

const text = "10 x source 4 50° on booms (2 downstage left and right, 2 upstage left and right) 2x festoons (mentioned above) 4x 1kx Fresnel backlight in L712 4x SL 15/32 (3x L443, 4x R119) – all four of which are specifically focused specials 1x Edison bulb suspended from grid";
const re = /\d+\s*x\b(?:\([^()]*\)|[^()])*?(?=\d+x|$)/gi;
document.body.innerHTML = "<pre>" + JSON.stringify(text.match(re), 0, 4) + "</pre>"

Angular 正则表达式拆分字符串 1x asd..... 2x asd

Angular Regex Split String 1x asd..... 2x asd

regex

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