如何从 url 中删除特殊字符？

Question

let ids = [String: [String]]

ids=%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D

附加并传递 url 参数后，在响应结构特殊符号中添加的响应失败 -> %5B%%

https://baseUrl/endpoint?ids=4566abef1c-4462-4g62-bcc5-5ae10547104c,1256efcf8c-6977-430d-b3ec-4ae80547101c

如何从 url 中删除 %22%5D？

此处代码：

let parms: [String: [String]]
let urlString = "\(baseUrl)/\(endpoint)"
Connector.requestSwiftyJson(
    url: urlString,
    requestType: .get,
    withParams: parms,
    loader: false
) { json, response, error in

Answer 1

您可以通过在将参数传递给解析器之前调整参数来删除不需要的字符，例如：

let adaptedParams = params.reduce(into: [String: String]()) { [=10=][.key] = .value.joined(separator: ",") }

Answer 2

“...如何从 url 中删除 %22%5D？”。试试这个：

 let ids = "%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D"
 let cleanUrl = ids.replacingOccurrences(of: "%22%5D", with: "")
 print("\n---> cleanUrl: \(cleanUrl) \n")

您还可以使用以下方法删除所有百分比编码：

   if let cleanUrl = ids.replacingOccurrences(of: "%5B", with: "") // [
    .replacingOccurrences(of: "%5D", with: "")  // ]
    .replacingOccurrences(of: "%22", with: "")  // "
    .removingPercentEncoding {  // other encoding
    
    print("\n---> cleanUrl: \(cleanUrl) \n")
}

Answer 3

有一个API删除百分比编码

let string = "ids=%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D"
let cleanedString = string.removingPercentEncoding

但是，如果您需要提取 UUID，可以使用正则表达式来完成

func extractUUID(from string : String) -> [String]
{
    let pattern = "[0-9a-f]{10}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}"
    let regex = try! NSRegularExpression(pattern: pattern)
    let matches = regex.matches(in: string, range: NSRange(string.startIndex..., in: string))
    return matches.map { match -> String in
        let range = Range(match.range, in: string)!
        return String(string[range])
    }
}

let uuids = extractUUID(from: "ids=%5B%4566abef1c-4462-4g62-bcc5-5ae10547104c%22,%20%1256efcf8c-6977-430d-b3ec-4ae80547101c%22%5D")
print(uuids)

注意：第一个UUID中的g是无效字符

如何从 url 中删除特殊字符？

How to remove special characters from url?

ios

swift

string

url