如何为单独的按钮进行单独的交互 | discord.py pycord

Question

如何在 pycord/discord.py.

中对不同的按钮进行不同的交互响应

代码：

@client.command()
async def test(ctx: commands.Context):
    button = Button(label="Click Below", custom_id="freefire",style=discord.ButtonStyle.green, emoji="<:freefire:944183849779335198>")
    button1 = Button(label="Click Below", custom_id="bgmi",style=discord.ButtonStyle.green, emoji="<:bgmi:944184219528208384>")

    async def free_fire(interaction: discord.Interaction):
        role = ctx.guild.get_role(944152201784336414)
        member = ctx.guild.get_member(interaction.user.id)
        if role in interaction.user.roles and interaction.custom_id== "freefire":
            await interaction.user.remove_roles(role)
            await interaction.response.send_message(f"{role} role has been taken from you", ephemeral=True)
        else:
            await member.add_roles(role)
            await interaction.response.send_message(f"{role} role has been given to you", ephemeral=True)
        

    button.callback = free_fire


    async def bgmi(interaction: discord.Interaction):
        role = ctx.guild.get_role(944152314200088667)
        member = ctx.guild.get_member(interaction.user.id)
        if role in interaction.user.roles and interaction.custom_id== "bgmi":
            await interaction.user.remove_roles(role)
            await interaction.response.send_message(f"{role} role has been taken from you", ephemeral=True)
        else:
            await member.add_roles(role)
            await interaction.response.send_message(f"{role} role has been given to you", ephemeral=True)
        

    button.callback = bgmi

当我单击第一个按钮时，它只是给出了最后一个按钮的角色，而其他按钮根本没有响应，控制台或任何地方都没有错误。

Answer 1

问题是您首先将 button.callback 设置为 free_fire，然后您将 button.callback 设置为 bgmi。这可以通过将第二个 button.callback = ... 更改为 button1.callback = ...

来解决

如何为单独的按钮进行单独的交互 | discord.py pycord

How to have separate interactions for separate buttons | discord.py pycord

python

discord

discord.py

nextcord

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