将一组数据的最后一个和第一个时间戳数据组合在一行中

Question

我有一个屏幕截图 table 我想获取用户屏幕截图时间开始和屏幕截图时间结束。我想创建一个查询，以便能够导出数据以提供给我的用户。

假设这是我的 table 数据。

scs_id	scs_tracker_id	created_at
1	1000	2022-02-22 00:00:00
2	1001	2022-02-22 04:00:00
3	1000	2022-02-22 01:00:00
4	1002	2022-02-22 12:00:00
5	1001	2022-02-22 08:00:00
3	1000	2022-02-22 02:00:00

我的预期输出应该是：

scs_tracker_id	screenshot_starts	screenshot_ends
1000	2022-02-22 00:00:00	2022-02-22 02:00:00
1001	2022-02-22 04:00:00	2022-02-22 08:00:00
1002	2022-02-22 12:00:00	2022-02-22 12:00:00

我目前正在玩的代码：

SELECT 
(SELECT MIN(created_at) FROM screen_shots GROUP BY scs_tracker_id ORDER BY scs_id ASC LIMIT 1) AS screenshot_starts,
(SELECT MAX(created_at) FROM screen_shots GROUP BY scs_tracker_id ORDER BY scs_id DESC LIMIT 1) AS screenshot_ends
FROM screen_shots

Answer 1

按跟踪器 ID 聚合，然后取 min/max 时间戳：

SELECT
    scs_tracker_id,
    MIN(created_at) AS screenshot_starts,
    MAX(created_at) AS screenshot_ends
FROM screen_shots
GROUP BY scs_tracker_id;

将一组数据的最后一个和第一个时间戳数据组合在一行中

Combining last and first timestamp data of a group data in 1 row

mysql

sql

mariadb