处理 wget 模块中的 404 未找到错误 python

Question

x=input('Enter Roll Number :')
str1 = "http://xxxxx/xxxx/students_uploads/"
str2 = x+"_P.jpg"
res = str1 + str2
filename = wget.download(res)

这个简单的代码将从我们学院下载学生的个人资料图片 website.The 如果我们输入正确的学生卷号，代码运行良好，这意味着该网站有一个关于该卷号的文件，但是当我们输入错误的卷号时它抛出

Exception                                 Traceback (most recent call last)
<ipython-input-20-cbbda742e201> in <module>
      4 str2 = x+"_P.jpg"
      5 res = str1 + str2
----> 6 filename = wget.download(res)

D:\Anaconda\lib\site-packages\wget.py in download(url, out, bar)
    314         callback = None
    315 
--> 316     (tmpfile, headers) = ThrowOnErrorOpener().retrieve(url, tmpfile, callback)
    317     names["header"] = filename_from_headers(headers)
    318     if os.path.isdir(names["out"]):

D:\Anaconda\lib\urllib\request.py in retrieve(self, url, filename, reporthook, data)
   1822             except OSError as msg:
   1823                 pass
-> 1824         fp = self.open(url, data)
   1825         try:
   1826             headers = fp.info()

D:\Anaconda\lib\urllib\request.py in open(self, fullurl, data)
   1788         try:
   1789             if data is None:
-> 1790                 return getattr(self, name)(url)
   1791             else:
   1792                 return getattr(self, name)(url, data)

D:\Anaconda\lib\urllib\request.py in open_http(self, url, data)
   1966     def open_http(self, url, data=None):
   1967         """Use HTTP protocol."""
-> 1968         return self._open_generic_http(http.client.HTTPConnection, url, data)
   1969 
   1970     def http_error(self, url, fp, errcode, errmsg, headers, data=None):

D:\Anaconda\lib\urllib\request.py in _open_generic_http(self, connection_factory, url, data)
   1960                               response.status)
   1961         else:
-> 1962             return self.http_error(
   1963                 url, response.fp,
   1964                 response.status, response.reason, response.msg, data)

D:\Anaconda\lib\urllib\request.py in http_error(self, url, fp, errcode, errmsg, headers, data)
   1982                 result = method(url, fp, errcode, errmsg, headers, data)
   1983             if result: return result
-> 1984         return self.http_error_default(url, fp, errcode, errmsg, headers)
   1985 
   1986     def http_error_default(self, url, fp, errcode, errmsg, headers):

D:\Anaconda\lib\site-packages\wget.py in http_error_default(self, url, fp, errcode, errmsg, headers)
    285 class ThrowOnErrorOpener(urllib.request.FancyURLopener):
    286     def http_error_default(self, url, fp, errcode, errmsg, headers):
--> 287         raise Exception("{0}: {1}".format(errcode, errmsg))
    288 
    289 def download(url, out=None, bar=bar_adaptive):

Exception: 404: Not Found

当有人输入错误的 rollnumber 时，有什么方法可以简单地将输出输出到 File not found enter correct roll number 。谢谢

Answer 1

围绕 wget.download 调用的简单异常捕获应该足够了：

try:
    filename = wget.download(res)
except Exception as exc:
    print(f"wget failed: {str(exc)}")

处理 wget 模块中的 404 未找到错误 python

Handling 404 not found error in wget module python

wget

python-3.x

anaconda