Scrapy 排除包含特定文本的 URL

Scrapy exclude URLs containing specific text

我在尝试构建 Scrapy Python 程序时遇到问题。代码如下。

import scrapy
from scrapy.spiders import CrawlSpider, Rule
from scrapy.linkextractors import LinkExtractor

class LinkscrawlItem(scrapy.Item):
    link = scrapy.Field()
    attr = scrapy.Field()

class someSpider(CrawlSpider):
  name = 'mysitecrawler'
  item = []

  allowed_domains = ['mysite.co.uk']
  start_urls = ['https://mysite.co.uk/']

  rules = (Rule (LinkExtractor(), callback="parse_obj", follow=True),
    Rule (LinkExtractor(deny=('my-account', 'cart', 'checkout', 'wp-content')))
  )

  def parse_obj(self,response):
    item = LinkscrawlItem()
    item["link"] = str(response.url)+":"+str(response.status)
    filename = 'links2.txt'
    with open(filename, 'a') as f:
      f.write('\n'+str(response.url)+":"+str(response.status)+'\n')
    self.log('Saved file %s' % filename)

我在使用 LinkExtractor 时遇到问题,对我来说,拒绝意味着从抓取中排除我提供的链接列表。但它仍在爬行它们。前三个网址是:

https://mysite.co.uk/my-account/

https://mysite.co.uk/cart/

https://mysite.co.uk/checkout/

最后一个包含wp-content,例如:

https://mysite.co.uk/wp-content/uploads/01/22/photo.jpg

有人知道我的拒绝名单有什么问题吗?

谢谢

您的代码有两个问题。首先,您的抓取蜘蛛中有两个 Rules 并且您在第二条规则中包含拒绝限制,该规则永远不会被检查,因为第一条规则遵循所有链接然后调用回调。因此,首先检查第一条规则,因此它不会排除您不想抓取的 urls。第二个问题是,在你的第二条规则中,你已经包含了你想要避免抓取的文字字符串,但 deny 需要正则表达式。

解决方案是删除第一条规则并通过转义 url 中的特殊正则表达式字符(例如 -)稍微更改 deny 参数。请参阅下面的示例。

import scrapy
from scrapy.spiders import CrawlSpider, Rule
from scrapy.linkextractors import LinkExtractor

class LinkscrawlItem(scrapy.Item):
    link = scrapy.Field()
    attr = scrapy.Field()

class SomeSpider(CrawlSpider):
    name = 'mysitecrawler'
    allowed_domains = ['mysite.co.uk']
    start_urls = ['https://mysite.co.uk/']

    rules = (
        Rule (LinkExtractor(deny=('my\-account', 'cart', 'checkout', 'wp\-content')), callback="parse_obj", follow=True),
    )

    def parse_obj(self,response):
        item = LinkscrawlItem()
        item["link"] = str(response.url)+":"+str(response.status)
        filename = 'links2.txt'
        with open(filename, 'a') as f:
            f.write('\n'+str(response.url)+":"+str(response.status)+'\n')
        self.log('Saved file %s' % filename)