error: column "userId" does not exist Sequelize many-to-many relationsip

Question

我尝试使用 Sequelize 在 Postgres 中创建用户和模板之间的多对多关系。但是当我尝试创建用户时出现以下错误并且找不到问题所在。

  Executing (default): INSERT INTO "users" ("id","createdAt","updatedAt") VALUES (DEFAULT,,) RETURNING "id","userId","templateId","createdAt","updatedAt"
error: column "userId" does not exist

用户模型

"use strict";
module.exports = (sequelize, DataTypes) => {
  const user = sequelize.define(
    "user",
    {
      name: DataTypes.STRING,
      email: DataTypes.STRING,
      phone: DataTypes.STRING,
      password: DataTypes.STRING
    },
    {}
  );
  user.associate = function(models) {
    user.belongsToMany(models.template, {through: 'User_Templates'})
  };
  return user;
};

模板模型

"use strict";
module.exports = (sequelize, DataTypes) => {
  const template = sequelize.define(
    "template",
    {
      name: DataTypes.STRING,
      html: DataTypes.STRING
    },
    {}
  );
  template.associate = function(models) {
    template.belongsToMany(models.user, {through: 'User_Templates'})
  };
  return template;
};

User_Template模型（结点table）

"use strict";
module.exports = (sequelize, DataTypes) => {
  const User_Template = sequelize.define(
    "user",
    {
      userId: DataTypes.INTEGER,
      templateId: DataTypes.INTEGER
    },
    {}
  );
  User_Template.associate = function(models) {
    User_Template.belongsTo(models.user, {
      foreignKey: 'userId',
      as: 'user'
    })
    User_Template.belongsTo(models.template, {
      foreignKey: 'templateId',
      as: 'template'
    })
  };
  return User_Template;
};

Answer 1

您通过为 User_Template 模型指定相同的名称 user 来重新定义 User 模型：

const User_Template = sequelize.define(
    "user",

改成User_Templates:

const User_Template = sequelize.define(
    "User_Templates",

error: column "userId" does not exist Sequelize many-to-many relationsip

error: column "userId" does not exist Sequelize many-to-many relationsip

postgresql

express

sequelize.js