属性 从相关模型中获取时此集合实例上不存在

Question

我有这个查询，其中 return 个数据来自 table :

$existData =Booking::where(function ($query)use($start, $end){
                                    $query->whereBetween('start', [
                                        $start, $end
                                    ])->orwhereBetween('end', [
                                        $start, $end]);
                                })->where('status','confirmed')->get();

这个 return 的数据但是当我添加关系到它时

$existData =Booking::where(function ($query)use($start, $end){
                                        $query->whereBetween('start', [
                                            $start, $end
                                        ])->orwhereBetween('end', [
                                            $start, $end]);
                                    })->where('status','confirmed')->with(['bookingDetails'=> function ($q) use($data){
                                    $q->where('user_type',$data->type);
                      
                                }])->get();

它给出错误：

Property [user_type] does not exist on this collection instance.

但我已经在预订模型中创建了关系

public function bookingDetails()
    {
        return $this->hasMany('App\Models\BookingRoomDetails', 'o_id', 'id');
    }

BookingDetailModel :

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class BookingRoomDetails extends Model
{
    use HasFactory;
}

如果外部查询和内部查询 return 为真，我希望整个查询应该只有 return 数据，例如。 $q->where('user_type',$utype->type); 并且时间范围存在并且已经可以正常工作。

解决此问题的任何解决方案

Answer 1

将查询代码更改为：

use Illuminate\Database\Eloquent\Builder;

$existData = Booking::with(['bookingDetails'=> function ($q) use ($data) {
    $q->where('user_type',$data->type);
}])->where(function (Builder $query) use ($start, $end) {
    return $query->whereBetween('start', [ $start, $end ])
        ->orwhereBetween('end', [ $start, $end ]);
})->where('status','confirmed')
->get();