我怎样才能收到元素的数量？

Question

test.js:

cy.get('.ant-input-number-input')
  .wait(2000)
  .then(($input_field) => {
    const count = $input_field.find('.ant-input-number-input').length;
    cy.log(count)
  })

cy.log:

log 0

我需要计算元素的数量。但我收到了“0”。如何接收元素计数？

Answer 1

您可以使用

const count = $input_field.find('.ant-input-number-input').its('length')

Answer 2

假设你只求元素.ant-input-number-input的长度，你可以这样做：

获取长度

cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .then((len) => {
    cy.log(len) //prints length
  })

如果你想添加断言，你可以这样做：

//Length equal to 2
cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .should('eq', 2)

//Length greater than 2
cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .should('be.gt', 2)

//Length greater than or equal to 2
cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .should('be.gte', 2)

//Length less than 2
cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .should('be.lt', 2)

//Length less than or equal to 2
cy.get('.ant-input-number-input')
  .should('be.visible')
  .its('length')
  .should('be.lte', 2)

我怎样才能收到元素的数量？

How can I receive count of elements?

cypress