如何为 XSLT 中的两组元素生成相同的随机数?
How to generate random number which is same for two set of elements in XSLT?
输入:
<paragraph>
<bq>34152</bq>
<eq>52325/eq>
<private type="DOB">SP1</private>
<bq>12431</bq>
<abc>EX</abc>
<eq>31333</eq>
</paragraph>
预期输出:
<paragraph>
<bq>55124</bq>
<eq>55124</eq>
<private type="DOB">SP1</private>
<bq>66565</bq>
<abc>EX</abc>
<eq>66565</eq>
</paragraph>
如何使用应用模板为每个 bq 和 eq 集生成相同的随机数?
在 XSLT 3 中(例如 random-number-generator
)它会归结为
<xsl:accumulator name="rng" as="map(*)" initial-value="random-number-generator(current-dateTime())">
<xsl:accumulator-rule match="paragraph/bq" select="$value?next()"/>
</xsl:accumulator>
<xsl:template match="paragraph/bq | paragraph/eq" expand-text="yes">
<xsl:copy>{round(accumulator-before('rng')?number * 100000)}</xsl:copy>
</xsl:template>
<xsl:mode on-no-match="shallow-copy" use-accumulators="rng"/>
这需要 Saxon HE 10 或更高版本或 Saxon PE/EE 9.8 或更高版本或 Saxon-JS 2.
输入:
<paragraph>
<bq>34152</bq>
<eq>52325/eq>
<private type="DOB">SP1</private>
<bq>12431</bq>
<abc>EX</abc>
<eq>31333</eq>
</paragraph>
预期输出:
<paragraph>
<bq>55124</bq>
<eq>55124</eq>
<private type="DOB">SP1</private>
<bq>66565</bq>
<abc>EX</abc>
<eq>66565</eq>
</paragraph>
如何使用应用模板为每个 bq 和 eq 集生成相同的随机数?
在 XSLT 3 中(例如 random-number-generator
)它会归结为
<xsl:accumulator name="rng" as="map(*)" initial-value="random-number-generator(current-dateTime())">
<xsl:accumulator-rule match="paragraph/bq" select="$value?next()"/>
</xsl:accumulator>
<xsl:template match="paragraph/bq | paragraph/eq" expand-text="yes">
<xsl:copy>{round(accumulator-before('rng')?number * 100000)}</xsl:copy>
</xsl:template>
<xsl:mode on-no-match="shallow-copy" use-accumulators="rng"/>
这需要 Saxon HE 10 或更高版本或 Saxon PE/EE 9.8 或更高版本或 Saxon-JS 2.