如何在 Sequelize 中加入两个查询

Question

我尝试连接两个查询并根据它找到结果。我可以在 SQL 中编写代码。我的 SQL 密码是

SELECT a.awbid, 
       m.mpscount
FROM ( select a.awbid 
       FROM awbmaster a 
       where a.batchid ='B/117/15022022' 
       and a.hubid ='117'
     ) as a 
left join ( select count('mpsid') as "mpscount" , 
                   awbid from 
                   mpsmaster m 
                   where m.batchid = 'B/117/15022022' 
                   group by "awbid"
          ) as m on a.awbid = m.awbid

但是，我还没有找到任何关于续集的解决方案。我如何在sequelize中编写上面的SQL代码？

Answer 1

首先，我们可以简化此 SQL 查询，只需使用子查询即可找出 mpscount:

SELECT a.awbid,
  (SELECT count(*)
   FROM mpsmaster m
   WHERE m.batchid = 'B/117/15022022'
     AND m.awbid=a.awbid ) AS mpscount
FROM awbmaster a
WHERE a.batchid ='B/117/15022022'
  AND a.hubid ='117'

现在如果我们已经有了两个模型 MpsMaster 和 AwbMaster 并且它们之间有正确的关联，那么我们可以发出这样的请求：

const records = AwbMaster.findAll(}
  attributes: [
   'awbid',
   [Sequelize.literal('(SELECT count(*) FROM mpsmaster m WHERE m.batchid = \'B/117/15022022\' AND m.awbid=AwbMaster.awbid)'), 'mpscount']
  ]
})

如何在 Sequelize 中加入两个查询

How to Join two Queries in Sequelize

sql

postgresql

node.js

sequelize.js