如何从 django-rest-swagger 将 swagger/?format=openapi 导入邮递员而不会出现格式错误

Question

我们的项目使用django-rest-swagger来管理API，我们想导出所有api并导入Postman，我可以得到JSON下面 url localhost:5000/swagger/?format=openapi，但是当我导入文件时，邮递员说 Error while importing: format not recognized，如何从 django-rest-swagger 导入 swagger/?format=openapi 到邮递员而不无法识别格式错误？

有没有人知道一些简单的解决方法？非常感谢任何建议!!!!!

{
swagger: "2.0",
info: {
title: "TestProjectAPI",
description: "",
version: ""
},
host: "localhost:5000",
schemes: [
"http"
],
paths: {
/api-token/: {
post: {
operationId: "api-token_post",
responses: {
201: {
description: ""
}
},
parameters: [
{
name: "data",
in: "body",
schema: {
type: "object",
properties: {
pic_id: {
description: "",
type: "string"
},
phonenumber: {
description: "",
type: "string"
},
checkcode: {
description: "",
type: "string"
},
user_phone: {
description: "",
type: "string"
},
phone_code: {
description: "",
type: "string"
},
username: {
description: "",
type: "string"
},
password: {
description: "",
type: "string"
}
}
}
}
],
description: "User Login",
summary: "User Login",
consumes: [
"application/json"
],
tags: [
"api-token"
]
}
},
/porject_management/: {
get: {
operationId: "porject_management_list",
responses: {
200: {
description: ""
}
},
parameters: [
{
name: "page",
required: false,
in: "query",
description: "A page number within the paginated result set.",
type: "integer"
},
{
name: "page_size",
required: false,
in: "query",
description: "Number of results to return per page.",
type: "integer"
},
{
name: "search",
required: false,
in: "query",
description: "A search term.",
type: "string"
},
{
name: "project",
required: false,
in: "query",
description: "",
type: "string"
},
{
name: "state",
required: false,
in: "query",
description: "",
type: "number"
},
{
name: "ordering",
required: false,
in: "query",
description: "Which field to use when ordering the results.",
type: "string"
}
],
description: "porject management",
summary: "porject management",
tags: [
"porject_management_post"
]
},
post: {
operationId: "porject_management_post",
responses: {
201: {
description: ""
}
},
parameters: [
{
name: "data",
in: "body",
schema: {
type: "object",
properties: {
project: {
description: "",
type: "string"
},
tc_code: {
description: "",
type: "string"
},
visitors_number: {
description: "",
type: "integer"
},
site_selection: {
description: "",
type: "string"
},
contact_name: {
description: "",
type: "string"
},
contact_number: {
description: "",
type: "string"
},
remark: {
description: "",
type: "string"
},
type: {
description: "",
type: "integer"
},
state: {
description: "",
type: "integer"
},
status: {
description: "",
type: "integer"
},
creater: {
description: "",
type: "string"
},
modifier: {
description: "",
type: "string"
}
}
}
}
],
description: "Porject management",
summary: "Porject management",
consumes: [
"application/json"
],
tags: [
"homemanager"
]
}
},
securityDefinitions: {
basic: {
type: "basic"
}
}
}

Answer 1

您尝试过使用：

python3 manage.py generateschema --file openapi-schema.yml

在终端？然后您可以直接将架构导入您的 POSTMAN。您正在提供 JSON 格式，对邮递员使用 yaml 格式应该可以。

Answer 2

最后，我通过 eolink.com,

解决了我的问题

首先，从 localhost:5000/swagger/?format=openapi

导入 JSON

其次，通过eolink.com导出Swagger，然后您可以将该文件导入邮递员！！！

如何从 django-rest-swagger 将 swagger/?format=openapi 导入邮递员而不会出现格式错误

How to import swagger/?format=openapi to postman from django-rest-swagger without error of format not recognized

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swagger