内部函数改变外部函数的变量值

Question

def swap(i,r,c,mat):

    for j in range(i+1,c):
        if(abs(mat[j][j])>0):
            mat[[j,i]] = mat[[i,j]]
            break

    return mat


def upper_triMat(matA,r,c):

    np.set_printoptions(precision=4)

    # forward elimination
    for i in range(0,c-1):
        if matA[i][i] == 0:
            matA = swap(i,r,c,matA)
    
    for j in range(i+1,r):
        multiplier = matA[j][i]/matA[i][i]
        for k in range(0,c):
            matA[j][k] = matA[j][k] - multiplier*matA[i][k]
                
    return matA


def dolittle(A):
 
    A = np.array(A)
    r,c = np.shape(A)
    print(A)
    U = upper_triMat(A,r,c) # Here the value of A is changed U. 
    print(A)
    l = np.eye(r,c)
    for i in range(0,r-1):
        for j in range(i+1,r):
            sum = 0
            for k in range(0,r):
                if i != k:
                    sum = sum + U[k][i]*l[j][k]
            l[j][i] = (A[j][i]-sum)/U[i][i]
        
    return l,U


A = [[3,-0.1,-0.2],
    [0.1,7,-0.3],
    [0.3,-0.2,10]]

dolittle(A)

当我调用 upper_triMat 函数“A”时 dolittle 功能。为什么？？ A 是 A 并且 upper_triMat 函数将其分配给 U 。但是 A 也得到了 U 的值。使用 Jupyter 笔记本。我在做 LU 分解

Answer 1

upper_triMat 改变其参数 matA。由于 matA 是对 A 的引用，因此它正在被修改。也许你可以这样解决

U = upper_triMat(A.copy(),r,c) # pass a copy of the list instead of the reference of the original one.

内部函数改变外部函数的变量值

inner function changing the variable value of outer function

numerical-analysis

python-3.x

jupyter-notebook