在 javascript 中返回 NaN 的函数

Question

我正在尝试编写一个函数来计算学生对象列表中的平均学生年龄，但是当我运行代码时，该函数打印 NaN 作为输出

function average_age(){
    let total = 0;
    students.forEach(s => {
        total += Number(s.age);
    });
    return  total/size
}
console.log("Average age is : " + average_age())

这就是我构建数组的方式（我得到了用户的输入）

const size = 5
let students = [size]

for (let i=1; i<=5; i++){
    let name = prompt("Enter student's name: ")
    let gender = prompt ("Enter student's gender: ")

    students.push({
        name: name,
        gender: gender,
        age:Math.round(Math.random() * (35 - 17 + 1) + 1),
        grade:Math.round(Math.random() * (100 + 1))
    })
}

//display student info
students.map(s =>{
    console.log("Name: " + s.name);
    console.log("gender: " + s.gender);
    console.log("age: " + s.age);
    console.log("grade: " + s.grade);
    console.log();
})

我试图计算学生年龄的总和（删除除法运算）以检查问题是否出在除法上，但我仍然得到 NaN 作为输出

Answer 1

您可以查看下面的 3 种方法来解决您的问题：

const students = [
  { id: 1, name: "john", age: 25 },
  { id: 2, name: "jack", age: 31 },
  { id: 3, name: "joe", age: 26 },
  { id: 4, name: "jamal", age: 21 },
];

// Your approach:
function average_age() {
  let total = 0;
  let numberOfStudents = students.length;
  
  students.map(student => {
    total += Number(student.age);
  });
  
  return total / numberOfStudents;
}

// Second approach:
function average_age_second() {
  let total = 0;
  let numberOfStudents = students.length;
  
  students.forEach(student => {
    total += Number(student.age);
  });
  
  return total / numberOfStudents;
}

// Third approach: 
function average_age_third() {
  let numberOfStudents = students.length;
  
  const total = students.reduce((partialSum, student) => partialSum + student.age, 0);
  
  return total / numberOfStudents;
}   

console.log("Average age is : " + average_age());
console.log("Average age is : " + average_age_second());
console.log("Average age is : " + average_age_third());

Answer 2

假设学生数组采用以下格式（在您收集输入后）：

let students = [
  { name: "aaaa" , gender: "male"  , age: 17, grade: 63 },
  { name: "bbbb" , gender: "male"  , age: 20, grade: 70 },
  { name: "yyyy" , gender: "female", age: 18, grade: 45 },
  { name: "zzzz" , gender: "female", age: 18, grade: 70 },
  { name: "xxxx" , gender: "male"  , age: 20, grade: 83 },
];

一种可能的解决方案如下：

let students = [
  { name: "aaaa" , gender: "male"  , age: 17, grade: 63 },
  { name: "bbbb" , gender: "male"  , age: 20, grade: 70 },
  { name: "yyyy" , gender: "female", age: 18, grade: 45 },
  { name: "zzzz" , gender: "female", age: 18, grade: 70 },
  { name: "xxxx" , gender: "male"  , age: 20, grade: 83 },
];
//------------------------------
function average_age(students){
let total = 0;
students.forEach(s => total +=s.age);
return total/students.length
}
//------------------------------
console.log("Average age is : " + average_age(students));

在 javascript 中返回 NaN 的函数

function returning NaN in javascript

javascript

nan