如何获取两个日期范围内的天数？

Question

我有日历 table，其中包含 2021 年 12 月的所有日期（我只会举例说明 table 中的一些日期，但是据了解，它实际上包含所述月份的所有日期）：

ID	date
01	2021-12-01
02	2021-12-02
03	2021-12-03
04	2021-12-04
05	2021-12-05

我有用户 table:

ID	name	num_employee
01	Andrew	101
02	Mary	102

我有table帮助

ID	date	num_employee
01	2021-12-03	101
02	2021-12-04	101
03	2021-12-03	102
04	2021-12-04	102
05	2021-12-05	101
06	2021-12-06	102

我有一个显示员工编号、姓名、出勤天数和缺勤天数的查询：

SELECT u.num_employee,
       u.name,
       a.date AS attendances,
        (SELECT GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM calendar
           WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
           AND NOT FIND_IN_SET(EXTRACT(DAY FROM date),a.date)) as faults FROM users u
JOIN (SELECT num_employee,
      GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM attendances
      WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
      GROUP BY num_employee) a ON a.num_employee = u.num_employee

通过上面的查询，我得到了这个：

num_employee	name	attendances	faults
101	Andrew	3,4,5	1,2,3,6,7,8,9,10...
102	Mary	3,4,6	1,2,5,7,8,9,10...

现在，重点是除了出勤 table，我还要考虑另一个table，叫做休假。这个table的结构如下：

id	initial_date	final_date	num_employee
01	2021-12-07	2021-12-09	101
02	2021-12-07	2021-12-09	102

并且考虑到这一点table，处理为休假的范围内的天数应该停止出现在“错误”列中。结果应如下所示：

num_employee	name	attendances	faults
101	Andrew	3,4,5	1,2,3,6,10...
102	Mary	3,4,6	1,2,5,10...

我如何调整我的查询以获得上述内容？

考虑到我正在使用的 MariaDB 版本，有问题的查询无法适应使用 CTE。我正在开发 phpMyAdmin。

Answer 1

由于 MySQL 和 MariaDB 的序列不好，所以你有一个日历 table 到运行是很好的。

因此需要另一个检索假期日期的子查询。

我在子选择中使用了 GROUP BY，因为一个月中可能有超过 1 个假期。

SELECT u.num_employee,
       u.name,
       a.date AS attendances,
        (SELECT GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM calendar
           WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
           AND NOT FIND_IN_SET(EXTRACT(DAY FROM date),a.date)
           AND NOT FIND_IN_SET(EXTRACT(DAY FROM date),vac.vac_days)) as faults 
FROM users u
LEFT JOIN  (SELECT num_employee,
      GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM attendances
      WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
      GROUP BY num_employee) a ON a.num_employee = u.num_employee
LEFT JOIN (SELECT v.`num_employee`, GROUP_CONCAT(DAY(c.`date`)) vac_days
FROM vacations v INNER JOIN calendar c ON c.`date` BETWEEN v.`initial_date` AND `final_date`
AND c. date BETWEEN '2021-12-01' AND '2021-12-31'
GROUP BY v.`num_employee`) vac ON vac.`num_employee` = u.num_employee

num_employee | name   | attendances | faults     
-----------: | :----- | :---------- | :----------
         101 | Andrew | 3,4,5       | 1,2,6,10,11
         102 | Mary   | 3,4,6       | 1,2,5,10,11

db<>fiddle here

FIND_IN_SET 需要一个字符串并且不适用于 NULL，因此您需要检查 NULL 值并替换它们

SELECT u.num_employee,
       u.name,
       a.date AS attendances,
        (SELECT GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM calendar
           WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
           AND NOT FIND_IN_SET(EXTRACT(DAY FROM date),IFNULL(a.date,''))
           AND NOT FIND_IN_SET(EXTRACT(DAY FROM date),IFNULL(vac.vac_days,''))
           ) as faults 
FROM users u
LEFT JOIN  (SELECT num_employee,
      GROUP_CONCAT(DISTINCT EXTRACT(DAY FROM date)) AS date FROM attendances
      WHERE date BETWEEN '2021-12-01' AND '2021-12-31'
      GROUP BY num_employee) a ON a.num_employee = u.num_employee
LEFT JOIN (SELECT v.`num_employee`, GROUP_CONCAT(DAY(c.`date`)) vac_days
FROM vacations v INNER JOIN calendar c ON c.`date` BETWEEN v.`initial_date` AND `final_date`
AND c. date BETWEEN '2021-12-01' AND '2021-12-31'
GROUP BY v.`num_employee`) vac ON vac.`num_employee` = u.num_employee

num_employee | name   | attendances | faults           
-----------: | :----- | :---------- | :----------------
         101 | Andrew | 3,4,5       | 1,2,6,10,11      
         102 | Mary   | 3,4,6       | 1,2,5,7,8,9,10,11

db<>fiddle here

如何获取两个日期范围内的天数？

How to get the days within a range of two dates?

mysql

sql

phpmyadmin

mariadb