在 OpenCV 中画一条线并 Python 超出给定点

Question

所以我的目标是在 opencv 中画一条在第二个给定点之后连续的线。

我画了一张图应该能更好地解释它。绿色绘图是我想要的线。它从第 1 点开始，到第 2 点不结束。

非常感谢您的帮助

Answer 1

在两点之间画一条线就像画一个三角形。我通过使用 x 轴和 y 轴上较大的距离得到一个比例，并通过将我的三角形放大到屏幕尺寸，我达到了你想要的线。

import cv2
import numpy as np

sizeofscr = 500

blank_image = np.zeros((sizeofscr,sizeofscr,3), np.uint8)

p1 = (290,230)
p2 = (100,100)

blank_image = cv2.circle(blank_image, p1, 10, (255, 0, 0), 2)
blank_image = cv2.circle(blank_image, p2, 10, (255, 0, 0), 2)

fx = abs(p1[0] - p2[0])
fy = abs(p1[1] - p2[1])

if (p1[0]+p1[1]) > (p2[0]+p2[1]):
    if fx < fy:
        temp = abs(sizeofscr - p1[1]) / fy

        fx = (temp * fx) + p1[0]
        fy = (temp * fy) + p1[1]

        blank_image = cv2.line(blank_image,(int(fx),int(fy)),p2,(0,0,255),3)

    else:
        temp = abs(sizeofscr - p1[0]) / fx
    
        fx = (temp * fx) + p1[0]
        fy = (temp * fy) + p1[1]
    
        blank_image = cv2.line(blank_image,(int(fx),int(fy)),p2,(0,0,255),3)    
else:
    if fx < fy:
        temp = abs(sizeofscr - p1[1]) / fy

        fx = (temp * fx) + p1[0]
        fy = (temp * fy) + p1[1]

        blank_image = cv2.line(blank_image,(int(fx),int(fy)),p1,(0,0,255),3)
    else:
        temp = abs(sizeofscr - p1[0]) / fx
    
        fx = (temp * fx) + p1[0]
        fy = (temp * fy) + p1[1]
    
    
        blank_image = cv2.line(blank_image,(int(fx),int(fy)),p1,(0,0,255),3)    

cv2.imshow("test",blank_image)
cv2.waitKey(0)

结果：

在 OpenCV 中画一条线并 Python 超出给定点

Draw a Line in OpenCV and Python beyond given points

python

opencv

line