Return group by SQL 中最小和最大函数的相应分类值

Question

我有一笔交易 table 包含以下列： TRANSACTION_ID,USER_ID,MERCHANT_NAME,TRANSACTION_DATE,金额

-1) query to find the first merchant a user transacts on

-2) query to find the last merchant a user transacts on

我尝试了以下方法

此查询应按照从第一个条目中选取分类值的方式进行分组

-)select USER_ID, Min(TRANSACTION_DATE),MERCHANT_NAME from transactions
Group by USER_ID

Answer 1

使用ROW_NUMBER我们可以尝试：

WITH cte AS (
    SELECT *, ROW_NUMBER() OVER (PARTITION BY USER_ID ORDER BY TRANSACTION_DATE) rn1,
              ROW_NUMBER() OVER (PARTITION BY USER_ID ORDER BY TRANSACTION_DATE DESC) rn2
    FROM transactions
)

SELECT USER_ID,
       MAX(CASE WHEN rn1 = 1 THEN MERCHANT_NAME END) AS FIRST_MERCHANT_NAME,
       MAX(CASE WHEN rn2 = 1 THEN MERCHANT_NAME END) AS LAST_MERCHANT_NAME
FROM cte
GROUP BY USER_ID;

Return group by SQL 中最小和最大函数的相应分类值

Return the corresponding categorical values for min and max functions in group by SQL

mysql

sql

pandas-groupby