我怎么知道 BroadcastReceiver 是否正常工作？

Question

我正在尝试做一个应用程序，可以将来自来电的 phone 号码（以及联系人姓名，仅当它已经注册时）发送到网络服务，所以我找到了这个 question 在这里，我按照以下方式实现了答案：

public class PhoneStateReceiver extends BroadcastReceiver {

public String phoneNumber;
public String contactName;
ShareUuid su = new ShareUuid();
String uuid;

@Override
public void onReceive(Context context, Intent intent) {
    // TODO: This method is called when the BroadcastReceiver is receiving an Intent broadcast.
    //throw new UnsupportedOperationException("Not yet implemented");
    Bundle extras = intent.getExtras();
    if (extras != null) {
        if (extras.getString("state").equals(TelephonyManager.EXTRA_STATE_RINGING)) {
            phoneNumber = extras.getString("incoming_number");
            Log.e("PhoneNumber", "onReceive: "+phoneNumber);

            String nombre_prueba = contactExists(context, phoneNumber);
            Log.e("nombre_prueba", nombre_prueba);

            uuid = su.getUuid();
            Log.e("UUID - PhoneStateReceiver", uuid);

            Uri uri = Uri.withAppendedPath(android.provider.ContactsContract.CommonDataKinds.Phone.CONTENT_FILTER_URI,Uri.encode(phoneNumber));
            Cursor rCursor = context.getContentResolver().query(uri,
                    new String[] {
                            ContactsContract.CommonDataKinds.Phone.CONTACT_ID},
                    null,null,null);

            String nombre = rCursor.getString(0);
            //new SendData(uuid, phoneNumber, nombre).execute();
            Log.e("rCursor", nombre);
        }
    }
}

public String contactExists(Context context, String number) {
    /// number is the phone number
    Uri lookupUri = Uri.withAppendedPath(
            ContactsContract.CommonDataKinds.Phone.CONTENT_FILTER_URI,
            Uri.encode(number));
    String[] mPhoneNumberProjection = {
            ContactsContract.CommonDataKinds.Phone._ID,
            ContactsContract.CommonDataKinds.Phone.NUMBER,
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
    };
    Cursor cur = context.getContentResolver().query(lookupUri,mPhoneNumberProjection, null, null, null);
    try {
        if (cur.moveToFirst()) {
            Log.d("Phone number ID", ContactsContract.CommonDataKinds.Phone._ID);
            Log.d("Phone number DISPLAY_NAME", ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
            contactName = ContactsContract.CommonDataKinds.Phone._ID;
            return contactName;
        }
    } finally {
        if (cur != null) cur.close();
        contactName = "Número no registrado";
    }

    return contactName;
}
}

}

并且没有编译错误，但是当我接到一个电话时，logcat 或“运行”部分没有显示任何内容，所以，我不知道它是否已经开始工作了，这是我来自 Android Manifest:

的 intent-filter

<receiver
        android:name=".PhoneStateReceiver"
        android:exported="true">
        <intent-filter>
            <action android:name="android.intent.action.PHONE_STATE" />
        </intent-filter>
    </receiver>

我认为这可能是我的错误，所以我按照此 tutotial 接收短信，但当我收到短信时它也没有显示任何内容。

我错过了什么？

Answer 1

我只是忘了在运行时请求权限，我在我的 onCreate 中添加了它并且完美运行：

    if (ContextCompat.checkSelfPermission(
            this, Manifest.permission.READ_PHONE_STATE
    )!= PackageManager.PERMISSION_GRANTED) {
        ActivityCompat.requestPermissions(this,
                new String[]{(Manifest.permission.READ_PHONE_STATE)},
                REQUEST_PERMISSION_PHONE_STATE);
    }
    if (ContextCompat.checkSelfPermission(
            this, Manifest.permission.READ_CONTACTS
    )!= PackageManager.PERMISSION_GRANTED) {
        ActivityCompat.requestPermissions(this,
                new String[]{(Manifest.permission.READ_CONTACTS)},
                REQUEST_PERMISSION_READ_CONTACTS);
    }
    if (ContextCompat.checkSelfPermission(
            this, Manifest.permission.READ_CALL_LOG
    )!= PackageManager.PERMISSION_GRANTED) {
        ActivityCompat.requestPermissions(this,
                new String[]{(Manifest.permission.READ_CALL_LOG)},
                REQUEST_PERMISSION_READ_CALL_LOG);
    }

我还修改了我的 PhoneStateReceiver class，当来电号码已经注册时，我在尝试获取联系人姓名时遇到了很多问题，我在 Whosebug 上发现了一些问题，但不幸的是 none他们中的一些人帮助了我（他们被弃用了解决方案），最后我设法让它与下面的代码一起工作，我希望它对其他人有帮助

public class PhoneStateReceiver extends BroadcastReceiver {

public String phoneNumber = "";
public String contactName = "";

@Override
public void onReceive(Context context, Intent intent) {
    try {
        String state = intent.getStringExtra(TelephonyManager.EXTRA_STATE);
        phoneNumber = intent.getStringExtra(TelephonyManager.EXTRA_INCOMING_NUMBER);

        if(state.equals(TelephonyManager.EXTRA_STATE_RINGING) && phoneNumber!=null){
            Toast.makeText(context,"Ringing State Number is - " + phoneNumber, Toast.LENGTH_SHORT).show();
            contactName = getContactName(context, phoneNumber);
           
        }
    }
    catch (Exception e){
        e.printStackTrace();
    }
}

public String getContactName(Context context, String phoneNumber) {
    if(phoneNumber == null){
        return null;
    }

    ContentResolver cr = context.getContentResolver();
    Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
    Cursor cursor = cr.query(uri, new String[] {ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
    if(cursor == null) {
        return null;
    }
    String contactName = "Contacto no registrado";
    if(cursor.moveToFirst()) {
        contactName = cursor.getString(0);
    }
    if(!cursor.isClosed()) {
        cursor.close();
    }
    return contactName;
}

}

我怎么知道 BroadcastReceiver 是否正常工作？

How do I know if BroadcastReceiver is working?

java

android

broadcastreceiver

android-broadcast

incoming-call