检查是否可以在 Python 字典中找到键值组合
Check if key-value combinations can be found in Python dict
我正在寻找一个函数 found_in_color_dict()
,它告诉我是否可以在 color_dict
中找到某个键值组合。函数returns分别为True或False。
color_dict = {"a":"blue", "b":"green", "c":"yellow", "d":"red", "e":"black", "f":"white"}
checkpoints_1 = {"a":"blue"}
checkpoints_2 = {"a":"green"}
checkpoints_3 = {"a":"blue", "d":"red"}
checkpoints_4 = {"a":"blue", "d":"red", "f":"white"}
checkpoints_5 = {"a":"blue", "d":"red", "f":"purple"}
根据示例,我希望得到以下结果:
found_in_color_dict(checkpoints_1)
>>> True
found_in_color_dict(checkpoints_2)
>>> False
found_in_color_dict(checkpoints_3)
>>> True
found_in_color_dict(checkpoints_4)
>>> True
found_in_color_dict(checkpoints_5)
>>> False
我只能想到复杂的方法来解决这个问题。但我想可能有一种简单的方法可以解决它,对吗?
您可以像这样使用 all()
:
color_dict = {"a":"blue", "b":"green", "c":"yellow", "d":"red", "e":"black", "f":"white"}
def found_in_color_dict(d):
global color_dict
return all(i in color_dict.items() for i in d.items())
测试代码:
checkpoints_1 = {"a":"blue"}
checkpoints_2 = {"a":"green"}
checkpoints_3 = {"a":"blue", "d":"red"}
checkpoints_4 = {"a":"blue", "d":"red", "f":"white"}
checkpoints_5 = {"a":"blue", "d":"red", "f":"purple"}
print(found_in_color_dict(checkpoints_1),
found_in_color_dict(checkpoints_2),
found_in_color_dict(checkpoints_3),
found_in_color_dict(checkpoints_4),
found_in_color_dict(checkpoints_5))
输出:
True False True True False
您可以使用 set.issubset
:
注:dict.itemview
作为集合
def found_in_color_dict(checkpoint):
return checkpoint.items() <= color_dict.items()
>>> found_in_color_dict(checkpoints_1)
True
>>> found_in_color_dict(checkpoints_2)
False
>>> found_in_color_dict(checkpoints_3)
True
>>> found_in_color_dict(checkpoints_4)
True
>>> found_in_color_dict(checkpoints_5)
False
我正在寻找一个函数 found_in_color_dict()
,它告诉我是否可以在 color_dict
中找到某个键值组合。函数returns分别为True或False。
color_dict = {"a":"blue", "b":"green", "c":"yellow", "d":"red", "e":"black", "f":"white"}
checkpoints_1 = {"a":"blue"}
checkpoints_2 = {"a":"green"}
checkpoints_3 = {"a":"blue", "d":"red"}
checkpoints_4 = {"a":"blue", "d":"red", "f":"white"}
checkpoints_5 = {"a":"blue", "d":"red", "f":"purple"}
根据示例,我希望得到以下结果:
found_in_color_dict(checkpoints_1)
>>> True
found_in_color_dict(checkpoints_2)
>>> False
found_in_color_dict(checkpoints_3)
>>> True
found_in_color_dict(checkpoints_4)
>>> True
found_in_color_dict(checkpoints_5)
>>> False
我只能想到复杂的方法来解决这个问题。但我想可能有一种简单的方法可以解决它,对吗?
您可以像这样使用 all()
:
color_dict = {"a":"blue", "b":"green", "c":"yellow", "d":"red", "e":"black", "f":"white"}
def found_in_color_dict(d):
global color_dict
return all(i in color_dict.items() for i in d.items())
测试代码:
checkpoints_1 = {"a":"blue"}
checkpoints_2 = {"a":"green"}
checkpoints_3 = {"a":"blue", "d":"red"}
checkpoints_4 = {"a":"blue", "d":"red", "f":"white"}
checkpoints_5 = {"a":"blue", "d":"red", "f":"purple"}
print(found_in_color_dict(checkpoints_1),
found_in_color_dict(checkpoints_2),
found_in_color_dict(checkpoints_3),
found_in_color_dict(checkpoints_4),
found_in_color_dict(checkpoints_5))
输出:
True False True True False
您可以使用 set.issubset
:
注:dict.itemview
作为集合
def found_in_color_dict(checkpoint):
return checkpoint.items() <= color_dict.items()
>>> found_in_color_dict(checkpoints_1)
True
>>> found_in_color_dict(checkpoints_2)
False
>>> found_in_color_dict(checkpoints_3)
True
>>> found_in_color_dict(checkpoints_4)
True
>>> found_in_color_dict(checkpoints_5)
False