用 where 连接两个 table

Question

我有两个来自两个视图的查询

查询 1：

SELECT sum(cancels) as cancelcount,codeprogram 
FROM CanceliTems 
WHERE date_save BETWEEN '1/21/2022' AND 
'2/20/2022' and usercode = 8066
GROUP By codeprogram

结果是：

cancelcount	codeprogram
7	3001
7	3002
2	3006

查询 2：

SELECT SUM(sellcount) sellcount,codeprogram,price 
FROM sells
WHERE date_save BETWEEN '1/21/2022' AND '2/20/2022' and usercode = 8066
GROUP By codeprogram,price

结果是：

sellcount	codeprogram	price
27	3001	10000
25	3000	20000
9	3006	25000
3	3011	15000
8	3008	11000
55	3002	50000

如何加入两个视图，然后从销售数量中减去取消数量，最后将数量乘以价格，在指定的日期范围内？

在每个视图中，我都有字段 date_save（日期时间），它由 getdate() 和用户代码填充。

finalcount = (sellcount - cancelcount) * price

我希望最终输出如下：

finalcount	codeprogram	price
20	3001	200000
25	3000	500000
7	3006	175000
3	3011	45000
8	3008	88000
47	3002	2350000

谢谢

Answer 1

您可以尝试将两个子查询与 OUTER JOIN

一起使用的一种方法

SELECT sellcount - ISNULL(cancelcount,0) finalcount,
       t1.codeprogram,
       t1.price
FROM (
    SELECT SUM(sellcount) sellcount,codeprogram,price 
    FROM sells
    WHERE date_save BETWEEN '1/21/2022' AND '2/20/2022' and usercode = 8066
    GROUP By codeprogram,price
) t1
LEFT JOIN (
    SELECT sum(cancels) as cancelcount,codeprogram 
    FROM CanceliTems 
    WHERE date_save BETWEEN '1/21/2022' AND '2/20/2022' and usercode = 8066
    GROUP By codeprogram
) t2 ON t1.codeprogram = t2.codeprogram

根据您的查询，您可以重写如下，使用 UNION ALL 结合 sells & CanceliTems 并制作一个标志来表示 1 是正数，2为负数则使用条件聚合函数。

SELECT SUM(CASE WHEN flag = 1 THEN sellcount ELSE - sellcount END),codeprogram,SUM(price) price
FROM (
    SELECT sellcount,codeprogram,price , 1 flag
    FROM sells
    WHERE date_save BETWEEN '1/21/2022' AND '2/20/2022' and usercode = 8066
    UNION ALL
    SELECT cancels,codeprogram,0 , 2
    FROM CanceliTems
    WHERE date_save BETWEEN '1/21/2022' AND '2/20/2022' and usercode = 8066
) t1
GROUP BY codeprogram

用 where 连接两个 table

Join two table with where

sql

sql-server

join